19/5:2x=1/4:8/3
Help me, please
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b, 4 ( x - 3 ) = 3
x - 3 = \(\dfrac{3}{4}\) = 0,75
x = 0,75 + 3 = 3,75
\(\dfrac{10^3+5\cdot10^2+5^2}{6^3+3\cdot6^2+3^3}=\dfrac{5^3\cdot2^3+5\cdot2^2\cdot5^2+5^2}{2^3\cdot3^3+3\cdot2^2\cdot3^2+3^3}\\ =\dfrac{5^3\left(2^3+2^2+1\right)}{3^3\left(2^3+2^2+1\right)}=\dfrac{5^3}{3^3}=\dfrac{125}{27}\)
5/x + y/4 = 1/8 ( Đề sai )
Đề đúng :
5/x - y/4 = 1/8
20/x.4 - y.x/4.x = 1/8
Suy ra x . 4 = 8
x = 2
y/4 = 5/2 - 1/8= 9.5/4
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4 + x = 7 - 2x
4 + x + 2x = 7
4 + 3x = 7
3x = 7 - 4
3x = 3
x = 3 : 3
x =1
5 + x = 8,3 + 4,7 - x
5 + x + x = 8,3 + 4,7
5 + 2x = 13
2x = 13 - 5
2x = 8
x = 8 : 2
x= 4
1, Vì A, B < 1
\(\Rightarrow B=\frac{19^{31}+5}{19^{32}+5}< \frac{19^{31}+5+90}{19^{32}+5+90}=\frac{19^{31}+95}{19^{32}+95}=\frac{19\left(19^{30}+5\right)}{19\left(19^{31}+5\right)}=\frac{19^{30}+5}{19^{31}+5}=A\)
2, Đề là thế này?? \(C=1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+...+\frac{1}{200}\left(1+2+3+...+200\right)\)
\(\Rightarrow C=1+\frac{1}{2}.\frac{2.3}{2}+\frac{1}{3}.\frac{4.3}{2}+...+\frac{1}{200}.\frac{200.201}{2}\)
\(\Rightarrow C=\frac{2}{2}+\frac{3}{2}+\frac{4}{2}+...+\frac{201}{2}\)
\(\Rightarrow C=\frac{\left(2+201\right).200}{4}=10150\)
\(a\left(\frac{1}{2}-\frac{1}{4}+....+\frac{1}{8}-\frac{1}{10}\right).y=\frac{1}{3}\)
\(\left(\frac{1}{2}-\frac{1}{10}\right).y=\frac{1}{3}\)
\(\frac{2}{5}.y=\frac{1}{3}\)
\(y=\frac{1}{3}:\frac{2}{5}\)
\(y=\frac{5}{6}\)
\(b,\left(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+....+\frac{1}{9}-\frac{1}{11}\right).y=\frac{2}{3}\)
\(\left(\frac{1}{1}-\frac{1}{11}\right).y=\frac{2}{3}\)
\(\frac{10}{11}.y=\frac{2}{3}\)
\(y=\frac{2}{3}:\frac{10}{11}\)
\(y=\frac{22}{30}\)
\(\frac{38}{10}:2x=\frac{1}{4}\times\frac{3}{8}\)
\(\frac{38}{10}:2x=\frac{3}{32}\)
\(2x=\frac{38}{10}:\frac{3}{32}\)
\(2x=\frac{38}{10}\times\frac{32}{3}\)
\(2x=\frac{608}{15}\)
\(x=\frac{608}{15}\times\frac{1}{2}\)
\(x=\frac{304}{15}\)