2x5³-36:3²
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a. = 125 + 170 + 1100 - 125 - 864 - 36 = 370
b. = 72 ( 7 + 3 ) + 52 ( 9 + 1 )
= 49 x 10 + 25 x 10
= 10 ( 49+25)
= 10 x 74 = 740
a.125+170+1100+(-125)+(-864)+(-36)
=1395+(-125)+(-864)+(-36)
=370
b.[(73+3.72)+(32.52+52)
=(343+3.49)+(9.25+25)
=(343+147)+(225+25)
=490+250
=740
\(B=\dfrac{3}{2\cdot5}+\dfrac{3}{5\cdot8}+\dfrac{3}{8\cdot11}+...+\dfrac{3}{26\cdot29}\)
\(B=\dfrac{1}{2}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{11}+...+\dfrac{1}{26}-\dfrac{1}{29}\)
\(B=\dfrac{1}{2}-\dfrac{1}{29}\)
\(B=\dfrac{27}{58}\)
B= 3/2x5 + 3/5x8+ 3/8x11 + ... + 3/26x29
B= 1/2 - 1/5 + 1/5 - 1/8 + 1/8 - 1/11 + ... + 1/26 - 1/29
B= 1/2-1/29
B=27/58
Ta có : A=3/2x5+3/5x8+3/8x11+3/11x14+3/14x17+3/17x20
=> A=1/2-1/5+1/5-1/8+1/8-1/11+1/11-1/14+1/14-1/17+1/17-1/20
=> A=1/2-1/20
=> A=9/20
Vậy A=9/20
đó
\(=0.04\cdot5-\dfrac{2^6\cdot3^{10}}{3^9\cdot2^6}=0.2-3=-2.8\)
\(920+3^2.\left(2^2.5^3-6.5^2\right)\\ \\ \\ =920+9.\left(4.125-6.25\right)\\ \\ \\ =920+9.\left(500-150\right)\\ \\ \\ =920+9.350=920+3150=4070\)
920 + 32 . (22 . 53 - 6 . 52)
= 920 + 9 . (4 . 125 - 6 . 25)
= 920 + 9 . (500 - 150)
= 920 + 9 . 350
= 920 + 3150
= 4070
`@` `\text {Ans}`
`\downarrow`
`A =`\(\dfrac{3}{2\times5}+\dfrac{3}{5\times8}+\dfrac{3}{8\times11}+...+\dfrac{3}{20\times23}+\dfrac{3}{23\times26}\)
`A=`\(\dfrac{1}{2}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{8}+...+\dfrac{1}{23}-\dfrac{1}{26}\)
`A=`\(\dfrac{1}{2}-\dfrac{1}{26}\)
`A=`\(\dfrac{6}{13}\)
Vậy, `A=`\(\dfrac{6}{13}\).
\(=2\cdot125-36:9=250-4=246\)