Tìm x biết
1 ) (-3)x /81 =-27
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a) \(3^{a+1}=81\)
\(3^{a+1}=3^4\)
\(a+1=4\)
\(a=3\)
b) \(\left(x-1\right)^3=27\)
\(\left(x-1\right)^3=3^3\)
\(x-1=3\)
\(x=4\)
\(a,3^{a+1}=81\\ \Rightarrow3^{a+1}=3^4\\ \\ \Rightarrow a+1=4\\ \Rightarrow a=3.\\ b,\left(x-1\right)^3=27\\ \Rightarrow\left(x-1\right)^3=3^3\\ \Rightarrow x-1=3\\ \Rightarrow x=4.\)
ta có :
\(\frac{x+1}{3}+\frac{x+1}{9}+\frac{x+1}{27}+\frac{x+1}{81}=\left(x+1\right)\times\left(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\right)\)
\(=\left(x+1\right)\times\frac{40}{81}=\frac{56}{81}\text{ nên }x+1=\frac{56}{40}=\frac{7}{5}\)
vậy \(x=\frac{7}{5}-1=\frac{2}{5}\)
\(\frac{1}{81}.27^x=3^x\Rightarrow\frac{1^2}{9^2}=\frac{3^x}{27^x}\)\(\Rightarrow\left(\frac{1}{9}\right)^2 =\left(\frac{1}{9}\right)^x\)\(\Rightarrow X=2\)
=>\(\frac{1}{3^4}\cdot\left(3^3\right)^x=3^x\)
=>\(\frac{3^{3x}}{3^4}=3^x\)
=>\(3x-4=x\)
=>\(3x=x+4\)
=>\(2x=4=>x=2\)
1) ( 2016 . 2016 - 2013 . 2009 ) . X = 18
( 4064256 - 4044117 ) . X = 18
0 . X = 18
X = 18 : 0
X = \(\varnothing\)
Vậy X = \(\varnothing\)
2) ( \(\frac{1}{3}\) + \(\frac{1}{9}\) + \(\frac{1}{27}\) + \(\frac{1}{81}\) + \(\frac{1}{243}\) ) . X = \(\frac{2}{3}\)
\(\frac{121}{243}\) . X = \(\frac{2}{3}\)
X = \(\frac{2}{3}\) : \(\frac{121}{243}\)
X = \(\frac{162}{121}\)
CHÚC BẠN HỌC TỐT
1) \(\frac{\left(-3\right)^x}{81}=-27\)
\(\Rightarrow\frac{\left(-3\right)^x}{\left(-3\right)^4}=\left(-3\right)^3\)
\(\Rightarrow\left(-3\right)^{x-4}=\left(-3\right)^3\)
\(\Rightarrow x-4=3\)
\(\Rightarrow x=7\)
Vậy x = 7
\(\left(-3\right)^x:81=-27\)
\(\left(-3\right)^x=81.\left(-27\right)=-2187\)
\(\left(-3\right)^x=\left(-3\right)^7\)
\(\Rightarrow x=7\)