1/ a/ So sánh 2^225 và 3^156
b/Tìm x biết : (2x.1)^2=16
MN giúp e mai ktra r ạ :<
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V
violet
Giáo viên
27 tháng 2 2021
Chào em, em tham khảo nhé!
1: The paparazzi had followed Princess Diana.
=> Princess Diana had been followed by the paparazzi.
2: Celebrities often accuse the paparazzi of putting lives in danger.
=> The paparazzi is often accused by celebrities of putting lives in danger.
3: The police arrested the photographer.
=>The photographer was arrested by the police.
4: The paparazzi have followed him everywhere.
=> He has been followed by the paparazzi everywhere.
5: Michael Douglas did not give the guests the location of the wedding.
=>The guests were not given the location of the wedding by Michael Douglas.
6: The paparazzi do not pay celebrities.
=> Celebrities are not paid by the paparazzi.
Chúc em học tốt và có những trải nghiệm tuyệt vời tại hoc24.vn!
27 tháng 2 2021
III> Rewrite using the correct passive form.
1: The paparazzi had followed Princess Diana. => Princess Diana had been followed by the paparazzi
2: Celebrities often accuse the paparazzi of putting lives in danger.
=> The paparazzi are often accused of putting lives in danger.
3: The police arrested the photographer.
=>The photographer was arrested by the police.
4: The paparazzi have followed him everywhere.
=> He has been followed everywhere by the paparazzi.
5: Michael Douglas did not give the guests the location of the wedding.
=>The guests weren't given the location of the wedding by Michael Douglas.
6: The paparazzi do not pay celebrities.
=> Celebrities aren't paid by the paparazzi.
HV
0
10 tháng 11 2021
\(a,ĐK:...\\ PT\Leftrightarrow x^2-6x=x^2-7x+10\\ \Leftrightarrow x=10\left(tm\right)\\ b,ĐK:...\\ PT\Leftrightarrow2x\left(4-x\right)-\left(2-2x\right)\left(8-x\right)=\left(8-x\right)\left(4-x\right)\\ \Leftrightarrow8x-2x^2+16+18x-2x^2=32-12x+x^2\\ \Leftrightarrow3x^2-38x+16=0\left(casio\right)\\ c,ĐK:...\\ PT\Leftrightarrow2x\left(x-4\right)-4x=0\\ \Leftrightarrow2x^2-12x=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\left(tm\right)\\x=6\left(tm\right)\end{matrix}\right.\)
Câu a) đề bài có sai không bạn?
b) \(\left(2x.1\right)^2=16\)
\(\Rightarrow\left(2x.1\right)^2=\left(\pm4\right)^2\)
\(\Rightarrow2x.1=\pm4.\)
\(\Rightarrow\left[{}\begin{matrix}2x.1=4\\2x.1=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=4\\2x=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=4:2\\x=\left(-4\right):2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)
Vậy \(x\in\left\{2;-2\right\}.\)
Chúc bạn học tốt!
Đề câu b sai thì phải?