4/8.9+4/9.10+...+4/70.71
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1/9.10 - ( 1/1.2 + 1/2.3 +...+ 1/8 .9)
= 1/9 - 1/10 -( 1/1 - 1/2 + 1/2 - 1/3 +. ..+1/8 - 1 9/)
= 1/9 - 1/10 - ( 1 - 1/9 )
= 1/9 - 1/10 - 1 + 1/9
=-79/9
thang Tran làm cách giải đúng rồi, nhưng đáp số là -79/90 nha.
Dù sao cũng cám ơn bạn vì giúp mình hiểu bài.
\(\frac{1}{9.10}-\frac{1}{8.9}-...-\frac{1}{1.2}\)
\(=-\left(\frac{1}{9.10}+\frac{1}{8.9}+...+\frac{1}{1.2}\right)\)
\(=-\left(\frac{1}{1.2}+\frac{1}{2.3}+....+\frac{1}{9.10}\right)\)
\(=-\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(=-\left(1-\frac{1}{10}\right)\)
\(=-\frac{9}{10}\)
\(\frac{1}{9.10}-\frac{1}{8.9}-....-\frac{1}{1.2}\)
\(=\frac{1}{9.10}-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{8.9}\right)\)
\(\Rightarrow\frac{1}{9.10}-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+....+\frac{1}{8}-\frac{1}{9}\right)\)
\(=\frac{1}{90}-\left(1-\frac{1}{9}\right)=\frac{1}{90}-\frac{80}{90}=\frac{-79}{90}\)
Lời giải:
$A=1.2+2.3+3.4+...+8.9+9.10$
$3A=1.2(3-0)+2.3(4-1)+3.4(5-2)+....+8.9(10-7)+9.10(11-8)$
$=(1.2.3+2.3.4+3.4.5+...+8.9.10+9.10.11)-(0.1.2+1.2.3+2.3.4+...+8.9.10)$
$=9.10.11$
$\Rightarrow A=\frac{9.10.11}{3}=330$
ta có 2/1.2+2/2.3+2/3.4+...+2/8.9+2/9.10
=2/1-2/2+2/2-2/3+2/3-2/4+...+2/8-2/9+2/9-2/10
=2/1-2/10
=9/5
Đặt A = \(\frac{2}{1.2}+\frac{2}{2.3}+\frac{2}{3.4}+...+\frac{2}{8.9}+\frac{2}{9.10}\)
\(A\times2=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{8.9}+\frac{1}{9.10}\)
\(A\times2=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\)
\(A\times2=\frac{1}{1}-\frac{1}{10}\)
\(A=\frac{9}{10}\times\frac{1}{2}=\frac{9}{20}\)
\(=4\left(\dfrac{1}{8\cdot9}+\dfrac{1}{9\cdot10}+...+\dfrac{1}{70\cdot71}\right)\\ =4\left(\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}+...+\dfrac{1}{70}-\dfrac{1}{71}\right)\\ =4\left(\dfrac{1}{8}-\dfrac{1}{71}\right)=4\cdot\dfrac{63}{568}=\dfrac{63}{142}\)