chứng minh
817 -279 - 9\(⋮\)45
810 -89 -88\(⋮\)55
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a) 7⁶ + 7⁵ - 7⁴
= 7⁴.(7² + 7 - 1)
= 7⁴.55 ⋮ 55
Vậy (7⁶ + 7⁵ - 7⁴) ⋮ 55
b) 81⁷ - 27⁹ + 3²⁹
= (3⁴)⁷ - (3³)⁹ + 3²⁹
= 3²⁸ - 3²⁷ + 3²⁹
= 3²⁶.(3² - 3 + 3³)
= 3²⁶.(9 - 3 + 27)
= 3²⁶.33 ⋮ 33
Vậy (81⁷ - 27⁹ + 3²⁹) ⋮ 33
\(=\left(7-8\right)+\left(9-10\right)+...+\left(87-88\right)+89\)
\(=\left(-1\right)+\left(-1\right)+...+\left(-1\right)+89\)
Số các số hạng từ 7 đến 88 là: \(88-7+1=82\) (số hạng)
\(=\left(-1\right)\cdot\left(82\div2\right)+89\)
\(=\left(-1\right)\cdot41+89\)
\(=\left(-41\right)+89\)
\(=48\)
a) \(7^6+7^5-7^4=7^4\left(7^2+7-1\right)=7^4\left(49+7-1\right)=7^4.55⋮55\)
b) \(16^5+2^{15}=\left(2^4\right)^5+2^{15}=2^{20}+2^{15}=2^{15}\left(2^5+1\right)=2^{15}\left(32+1\right)=2^{15}.33⋮33\)
c) \(81^7-27^9-9^{13}=\left(3^4\right)^7-\left(3^3\right)^9-\left(3^2\right)^{13}=3^{28}-3^{27}-3^{26}=3^{26}\left(3^2-3-1\right)=3^{26}.5=3^{22}.3^4.5=3^{22}.405⋮405\)
a: \(=7^4\left(7^2+7-1\right)=7^4\cdot55⋮55\)
b: \(=2^{20}+2^{15}=2^{15}\left(2^5+1\right)=2^{15}\cdot33⋮33\)
c: \(=3^{28}-3^{27}-3^{26}=3^{26}\left(3^2-3-1\right)=3^{26}\cdot5=3^{22}\cdot405⋮405\)
\(\dfrac{x-9}{55}+\dfrac{x-10}{66}=\dfrac{x-11}{77}+\dfrac{x-12}{88}\\ \Leftrightarrow\left(\dfrac{x-9}{55}+\dfrac{1}{11}\right)+\left(\dfrac{x-10}{66}+\dfrac{1}{11}\right)-\left(\dfrac{x-11}{77}+\dfrac{1}{11}\right)-\left(\dfrac{x-12}{88}+\dfrac{1}{11}\right)=0\)
\(\Leftrightarrow\left(\dfrac{x-9}{55}+\dfrac{5}{55}\right)+\left(\dfrac{x-10}{66}+\dfrac{6}{66}\right)-\left(\dfrac{x-11}{77}+\dfrac{7}{77}\right)-\left(\dfrac{x-12}{88}+\dfrac{8}{88}\right)=0\)
\(\Leftrightarrow\dfrac{x-4}{55}+\dfrac{x-4}{66}-\dfrac{x-4}{77}-\dfrac{x-4}{88}=0\)
\(\Leftrightarrow\left(x-4\right)\left(\dfrac{1}{55}+\dfrac{1}{66}-\dfrac{1}{77}-\dfrac{1}{88}\right)=0\\ \Leftrightarrow x=4\left(vì.\dfrac{1}{55}+\dfrac{1}{66}-\dfrac{1}{77}-\dfrac{1}{88}\ne0\right)\)
Ta có : 810 - 89 - 88
\(\Leftrightarrow\)88. ( 82 - 8 - 1 )
\(\Leftrightarrow\)88. 55 \(⋮\)55
Do đó : 810 - 89 - 88 \(⋮\)55