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13 tháng 10 2019

a) x4 + 3x3 - 7x2 - 27x - 18

= x4 + x3 + 2x3 + 2x2 - 9x2 - 9x - 18x - 18

= x3 . (x + 1) + 2x2 . (x + 1) - 9x . (x + 1) - 18(x + 1)

= (x + 1)(x3 + 2x2 - 9x - 18)

= (x + 1)[x2 .(x + 2) - 9.(x + 2)]

= (x + 1)(x + 2)(x2 - 32)

= (x + 1)(x + 2)(x + 3)(x - 3)

b) x4 + 3x3 + 3x2 + 3x + 2

= x4 + x3 + 2x3 + 2x2 + x2 + x + 2x + 2

= x3 (x + 1) + 2x2 . (x + 1) + x(x + 1) + 2(x + 1)

= (x + 1)(x3 + 2x2 + x + 2)

= (x + 1)[x2 .(x + 2) + (x + 2)]

= (x + 1)(x + 2)(x2 + 1)

13 tháng 10 2019

\(x^4+3x^3-7x^2-27x-18\)

\(=\left(x^4+x^3\right)+\left(2x^3+2x^2\right)-\left(9x^2+9x\right)-\left(18x-18\right)\)

\(=x^3\left(x+1\right)+2x^2\left(x+1\right)-9x\left(x+1\right)-18\left(x+1\right)\)

\(=\left(x+1\right)\left(x^3+2x^2-9x-18\right)\)

\(=\left(x+1\right)\left[\left(x^3-3x^2\right)+\left(5x^2-15x\right)+\left(6x-18\right)\right]\)

\(=\left(x+1\right)\left[x^2\left(x-3\right)+5x^2\left(x-3\right)+6\left(x-3\right)\right]\)

\(=\left(x+1\right)\left(x-3\right)\left(x^2+5x+6\right)\)

\(=\left(x+1\right)\left(x-3\right)\left(x+2\right)\left(x+3\right)\)

\(=\left(x+1\right)\left(x+2\right)\left(x+3\right)^2\)

Thực hiện phép tínha) \(\frac{\text{x + 9}}{x^2 - 9}-\frac{\text{3}}{\text{x^2 + 3x}}\)b) \(\frac{\text{3x + 5 }}{\text{x^2 - 5x }}+\frac{\text{ 25 - x }}{\text{25 - 5x }}\)c) \(\frac{\text{3 }}{\text{2x }}+\frac{\text{3x - 3 }}{\text{2x - 1 }}+\frac{ 2x^2 + 1 }{\text{4x^2 - 2x }}\)d) \(\frac{\text{1}}{\text{3x - 2 }}-\frac{1}{\text{3x + 2 }}- \frac{\text{3x - 6}}{\text{4 - 9x^2}}\)e) \(\frac{\text{18 }}{\text{(x - 3)(x^2 - 9) }}-\frac{\text{3 }}{\text{x^2 - 6x + 9...
Đọc tiếp

Thực hiện phép tính
a) \(\frac{\text{x + 9}}{x^2 - 9}-\frac{\text{3}}{\text{x^2 + 3x}}\)

b) \(\frac{\text{3x + 5 }}{\text{x^2 - 5x }}+\frac{\text{ 25 - x }}{\text{25 - 5x }}\)

c) \(\frac{\text{3 }}{\text{2x }}+\frac{\text{3x - 3 }}{\text{2x - 1 }}+\frac{ 2x^2 + 1 }{\text{4x^2 - 2x }}\)

d) \(\frac{\text{1}}{\text{3x - 2 }}-\frac{1}{\text{3x + 2 }}- \frac{\text{3x - 6}}{\text{4 - 9x^2}}\)
e) \(\frac{\text{18 }}{\text{(x - 3)(x^2 - 9) }}-\frac{\text{3 }}{\text{x^2 - 6x + 9 }}-\frac{\text{x}}{\text{x^2 - 9}}\)
g) \(\frac{\text{x + 2 }}{\text{x + 3 }}-\frac{\text{5 }}{\text{x^2 + x - 6 }}+\frac{\text{1}}{\text{2 - x}}\)
h) \(\frac{\text{4x }}{\text{x + 2 }}-\frac{\text{3x }}{\text{x - 2 }}+\frac{\text{12x}}{\text{x^2 - 4}}\)
i) \(\frac{\text{ x + 1 }}{\text{ x - 1 }}-\frac{\text{ x - 1 }}{\text{ x + 1 }}-\frac{\text{4}}{\text{1 - x^2}}\)
k) \(\frac{\text{ 3x + 21 }}{\text{ x^2 - 9 }}+\frac{\text{2 }}{\text{x + 3 }}-\frac{\text{3}}{\text{x - 3}}\)

 

0

\(\frac{5.2^{18}.3^{18}.2^{12}-2.2^{28}.3^{14}.3^4}{5.2^{28}.3^{18}-7.2^{29}.3^{18}}=\frac{5.2^{30}.3^{18}-2^{29}.3^{18}}{5.2^{28}.3^{18}-7.2^{29}.3^{18}}=\frac{2^{29}.3^{18}\left(5.2-1\right)}{2^{28}.3^{18}\left(5-7.2\right)}\)

\(\frac{2^{29}.3^{18}.9}{2^{28}.3^{18}.-9}=\frac{2.9}{-9}=-2\)

10 tháng 3 2020

ko phải tìm x nha

26 tháng 12 2021

a: =5(2x+3y)

d: =(x+1-y)(x+1+y)

NV
15 tháng 10 2019

\(=x^4+6x^3+5x^2-x^3-6x^2-5x-6x^2-36x-30\)

\(=x^2\left(x^2+6x+5\right)-x\left(x^2+6x+5\right)-6\left(x^2+6x+5\right)\)

\(=\left(x^2-x-6\right)\left(x^2+6x+5\right)\)

\(=\left(x-3\right)\left(x+2\right)\left(x+1\right)\left(x+5\right)\)

18 tháng 12 2021

mình cần gấp mong các bạn giải giùm

 

18 tháng 12 2021

c: \(E=\dfrac{\left(x-5\right)^2}{x\left(x-5\right)}=\dfrac{x-5}{x}\)

3 tháng 10 2019

\(B=x^3+3x^2+3x^2y+3xy^2+y^3+3y^2+6xy+3x+3y+2019\)

\(=\left(x+y\right)^3-3\left(x+y\right)^2+3\left(x+y\right)+2019\)

\(=\left[\left(x+y\right)^3-3\left(x+y\right)^2+3\left(x+y\right)+1\right]+2018\)

\(=\left(x+y-1\right)^3+2018\)

\(x+y=101\)

\(B=\left(101-1\right)^3+2018=1002018\)

3 tháng 10 2019

Đang 3x2+3y2 sao lại ra -3(x+y)2 ?? Phải là +3(x2+y2) chứ :v Không nhớ hằng đẳng thức 1 và 3 à :v với cả 6xy đâu?

24 tháng 12 2021

\(=2\left[\left(x-3\right)^2-\dfrac{1}{16}\left(x-1\right)^2\right]\\ =2\left(x-3-\dfrac{1}{4}x+\dfrac{1}{4}\right)\left(x-3+\dfrac{1}{4}x-\dfrac{1}{4}\right)\\ =2\left(\dfrac{3}{4}x-\dfrac{11}{4}\right)\left(\dfrac{5}{4}x-\dfrac{13}{4}\right)\)

10 tháng 11 2021

a.\(A=\dfrac{x^2-4x+4}{x^3-2x^2-\left(4x-8\right)}=\dfrac{\left(x-2\right)^2}{x^2\left(x-2\right)-4\left(x-2\right)}=\dfrac{\left(x-2\right)^2}{\left(x^2-4\right)\left(x-2\right)}=\dfrac{x-2}{\left(x-2\right)\left(x+2\right)}=\dfrac{1}{x+2}\)

 

10 tháng 11 2021

\(A=\dfrac{\left(x-2\right)^2}{x^2\left(x-2\right)-4\left(x-2\right)}\left(x\ne\pm2\right)\\ A=\dfrac{\left(x-2\right)^2}{\left(x-2\right)^2\left(x+2\right)}=\dfrac{1}{x+2}\\ B=\dfrac{x+2-x+\sqrt{x}-1}{\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}\cdot\dfrac{4\sqrt{x}}{3}\left(x>0\right)\\ B=\dfrac{4\sqrt{x}\left(\sqrt{x}+1\right)}{3\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}=\dfrac{4\sqrt{x}}{3\left(x-\sqrt{x}+1\right)}\)