53.(3x+2):13=103:(135:134)
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a, 71.2 – 6.(2x+5) = 10 5 : 10 3
71.2 – 6.(2x+5) = 10 2
6.(2x+5) = 71.2 – 100
6.(2x+5) = 42
x = 1
b, 5 x + 3 4 . 6 8 = 6 9 . 3 4
5 x + 3 4 . 6 8 = 6 8 . 6 . 3 4
5 x + 3 4 = 6 8 . 6 . 3 4 : 6 8 = 6 . 3 4
5x = 6 . 3 4 - 3 4 = 5 . 3 4
x = 3 4
c, 12:{390:[5. 10 2 – ( 5 3 + x . 7 2 )]} = 4
390:[5. 10 2 – ( 5 3 + x . 7 2 )] = 12:4 = 3
5. 10 2 – ( 5 3 + x . 7 2 ) = 390:3 = 130
5 3 + x . 7 2 = 5. 10 2 – 130 = 370
x . 7 2 = 370 – 5 3 = 245
x = 245: 7 2 = 5
d, 5 3 .(3x+2):13 = 10 3 : 13 5 : 13 4
5 3 .(3x+2):13 = 10 3 : 13
3x+2 = 10 3 : 13 : 5 3 .13 = 8
x = 2
\(\frac{54\times107-53}{53\times107+54}=\frac{53\times107+107-53}{53\times107+54}=\frac{53\times107+54}{53\times107+54}=1\)
\(\frac{135\times269-134}{134\times269+135}=\frac{134\times269+269-134}{134\times269+135}=\frac{134\times269+135}{134\times269+135}=1\)
THAM KHẢO :
A = 53.107 + 54 53 + 1 .107 − 53
= 53.107 + 54 53.107 + 107 − 53
= 53.107 + 54 53.107 + 54 = 1.
B = 134.269 + 135 134 + 1 .269 − 133
= 134.269 + 135 134.269 + 269 − 133
= 134.269 + 135 134.269 + 136 > 1
⇒A < B
\(A=\frac{\left(53+1\right).107-53}{53.107+54}=\frac{53.107+107-53}{53.107+54}=\frac{53.107+54}{53.107+54}=1.\)
\(B=\frac{\left(134+1\right).269-133}{134.269+135}=\frac{134.269+269-133}{134.269+135}=\frac{134.269+136}{134.269+135}>1\)
\(\Rightarrow A< B\)
A = 13 + 132 + 133 + 134 + 135 + 136
A = (13 + 132) + ( 133 + 134) + (135 + 136)
A = 13 \(\times\) ( 1 + 13) + 133 \(\times\) ( 1 + 13) + 135 \(\times\) ( 1 + 13)
A = 13 \(\times\) 14 + 133 \(\times\) 14 + 135 \(\times\) 14
A = 14 \(\times\) ( 13 + 133 + 135) vì 14 ⋮ 2
⇒ A ⋮ 2 ( đpcm)
\(5^3.\left(3x+2\right):13=10^3:\left(13^5:13^4\right)\)
\(125.\left(3x+2\right):13=1000:13\)
\(125.\left(3x+2\right)=1000\)
\(3x+2=1000:125\)
\(3x+2=8\)
\(3x=6\)
\(x=2\)
Hok tốt nha^^
=>53.(3x+2):13=103: 13
=>53.(3x+2)=103
=>(3x+2)=53
=>3x+2=5
=>3x=3
=>x=3:3
=>x=1