Question

[Tạ Nguyễn Huyền Giang]

Tính giá trị biểu thức :

G = \(\sqrt{\left(2-\sqrt{6}\right)^2}\)\(+\sqrt{\left(5-\sqrt{6}\right)^2}\)+\(\sqrt{\left(-2\right)^6}\)

F = \(\sqrt{7+4\sqrt{3}}\)\(-\sqrt{4-2\sqrt{3}}\)\(+\sqrt{\left(-2\right)^{10}}\)

H = \(6\sqrt{\frac{1}{6}}\)\(-\frac{4}{\sqrt{10}-\sqrt{6}}\)\(+\frac{10-\sqrt{10}}{\sqrt{10}-1}\)

NHANH NHÉ !!!!!

THANKS !!!!   

Answer 1

[Vũ Tiến Manh]

G = \(\sqrt{6}-2+5-\sqrt{6}+2^3=3+8=11\)

F= \(\sqrt{\left(2+\sqrt{3}\right)^2}-\sqrt{\left(\sqrt{3}-1\right)^2}+\sqrt{\left(2^5\right)^2}\)=\(2+\sqrt{3}-\sqrt{3}+1+2^5=3+32=35\)

H = \(\sqrt{6}-\frac{4\left(\sqrt{10}+\sqrt{6}\right)}{10-6}+\frac{\sqrt{10}\left(\sqrt{10}-1\right)}{\sqrt{10}-1}\)=\(\sqrt{6}-\sqrt{10}-\sqrt{6}+\sqrt{10}=0;\)