Giúp mình giải đề
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Part 1 :
1. so
2. forward
3. which
4.didn't
5. if
6. although
Part 2 :
1.C
2.E
3.A
4.F
5.B
6.D
Part 1:
1. with
2. does
3. after
4. if
5. where
6. I won't
Part 2:
1B 2F 3A 4E 5C 6D
Part 3:
1. invited
2. will play
3. have just won
4. be cleaned
5. to take
6. beautifully
7. impression
Part 4:
1. read -> reading
2. disappointing -> disappointed
3. environment -> environmental
4. who -> that
Part 5:
1. the bad weather
2. are made to study
3. were good at learning
4. going to the English
Part 1
1 if
2 after
3 that
4 so
5 should
6 from
Part 2
1b 2e 3a 4f 5c 6d
Part 3
1 conservationists
2 to take
3 hasn't provided
4 works
5 disappointed
6 achievement
7 polluted
8 dissolve
Part 4
1 will get -> get
2 amazing -> amazed
Part 5
1 use fresh water economically
2 school because the bus
3 they should keep
4 which is in this
Part 6
1 fond
2 watching
3 listened
4 or
Part 7
1T 2F 3T 4F
a)\(n_{Al}=\dfrac{8,1}{27}=0,3mol\)
\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
0,3 0,45 0,15 0,45
b)\(V_{H_2}=0,45\cdot22,4=10,08l\)
c)\(CuO+H_2\rightarrow Cu+H_2O\)
0,45 0,45 0,45
\(m_{Cu}=0,45\cdot64=28,8g\)
nAl = 8,1 : 27 = 0,3 (mol)
pthh : 2Al + 6 HCl ---> 2AlCl3 + 3H2
0,3 ----------------------------->0,45 (mol)
=> VH2= 0,45 . 22,4 = 10,08 (l)
pthh : CuO + H2 -t--> Cu + H2O
0,45------->0,45 (mol)
mCu = 0,45 . 64 = 28,8 (g)
Câu 5:
Áp dụng bất đẳng thức AM - GM ta có: \(\dfrac{P}{1152}=\dfrac{\sqrt{a-1}}{a}+\dfrac{\sqrt{b-9}}{b}+\dfrac{\sqrt{c-16}}{c}=\dfrac{\sqrt{a-1}}{\left(a-1\right)+1}+\dfrac{\sqrt{b-9}}{\left(b-9\right)+9}+\dfrac{\sqrt{c-16}}{\left(c-16\right)+16}\le\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{8}=\dfrac{19}{24}\Rightarrow P\le912\).
Đẳng thức xảy ra khi a = 2, b = 18, c = 32.
Vậy...