Hoàn thành chuỗi biến hóa sau:
a, Fe → FeCl2 ⇌ FeCl3 → Fe(OH)3 → Fe2O3 → CO2 → Na2CO3 → NaCl → NaNO3
b, FeS → H2S → CuS → SO2 ⇌ S
Giups vs ạ
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1,
KClO3(nhiệt phân) => KCl+O2
O2 + Fe(nhiệt độ) => Fe3O4
Fe3O4+CO => Fe+CO2
Fe+Cl2(nhiệt độ) => FeCl3
FeCl3+Ba(OH)2 => BaCl2+Fe(OH)3
Fe(OH)3+CuSO4 => Fe2(SO4)3+Cu(OH)2
2,
S+O2 => SO2
SO2+O2 => SO3
SO3+H2O => H2SO4
H2SO4đặc,nóng+Cu => CuSO4+SO2+H2O
CuSO4+BaCl2 => CuCl2+BaSO4
CuCl2 +AgNO3 => Cu(NO3)2 + AgCl
3,
Fe + S => FeS
FeS + 2HCl => FeCl2 + H2
H2S + O2 => SO2 + H2O
SO2+ NaOH => Na2SO3 +H2O
Na2SO3 + BaCl2 => BaSO4 + NaCl
NaCl + HNO3 => NaNO3 + HCl
4,
Na2SO4 + H2SO4 => Na2SO4 + SO2 + H2O
SO2 + O2 =>2SO3
SO3 + H2O => H2SO4
H2SO4 + BaCl2 => BaSO4 + 2HCl
Fe+ 2HCl=> FeCl2 + H2
FeCl2 +2AgNO3 => Fe(NO3)2 + AgCl
S + H2 ---to---> H2S
H2S + 2NaOH → Na2S + 2H2O
Fe(NO3)2 + Na2S → FeS + 2NaNO3
FeS + 2HCl → FeCl2 + H2S
2FeCl2 + Cl2 → 2FeCl3
FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl
4FeS + 7O2 ---to---> 2Fe2O3 + 4SO2
2Mg + SO2 → 2MgO + S
S + H2 ---to---> H2S
2H2S + 3O2 ---to---> 2H2O + 2SO2
2SO2 + O2 ---to V2O5---> 2SO3
SO3 + H2O → H2SO4
Ba + H2SO4 → BaSO4 + H2
2AlCl3+3Na2S->Al2S3+6NaCl
2AlCl3+3Na2S+6H2O->2Al(OH)3+3H2S+6NaCl
2Fe(NO3)3+3Na2CO3+6H2O->2Fe(OH)3+3CO2+6NaNO3
4CuFeS2 + 13O2 –> 4CuO + 2Fe2O3 + 8SO2
\(2AlCl_3+3Na_2S\rightarrow Al_2S_3+6NaCl\)
\(2AlCl_3+3Na_2S+6H_2O\rightarrow2Al\left(OH\right)_3+3H_2S+6NaCl\)
\(2Fe\left(NO_3\right)_3+3Na_2CO_3+3H_2O\rightarrow2Fe\left(OH\right)_3+3CO_2+6NaNO_3\)
\(2CuFeS_2+\dfrac{13}{2}O_2\rightarrow2CuO+Fe_2O_3+4SO_2\)
\(c,C+O_2\xrightarrow{t^o}CO_2\\ CO_2+2NaOH\to Na_2CO_3+H_2O\\ Na_2CO_3+2HCl\to 2NaCl+H_2O+CO_2\uparrow\\ NaCl+AgNO_3\to AgCl\downarrow+NaNO_3\\ d,4Fe+3O_2\xrightarrow{t^o}2Fe_2O_3\\ Fe_2O_3+6HCl\to 2FeCl_3+3H_2O\\ FeCl_3+3NaOH\to Fe(OH)_3\downarrow+3NaCl\\ 2Fe(OH)_3+3H_2SO_4\to Fe_2(SO_4)_3+6H_2O\\ Fe_2(SO_4)_3+3BaCl_2\to 3BaSO_4\downarrow+2FeCl_3\)
c) C + O2 --to--> CO2
2NaOH + CO2 --> Na2CO3 + H2O
Na2CO3 + 2HCl --> 2NaCl + CO2 + H2O
NaCl + AgNO3 --> AgCl\(\downarrow\) + NaNO3
d) 4Fe + 3O2 --to--> 2Fe2O3
Fe2O3 + 6HCl --> 2FeCl3 + 3H2O
FeCl3 + 3NaOH --> Fe(OH)3\(\downarrow\) + 3NaCl
\(2Fe\left(OH\right)_3+3H_2SO_4->Fe_2\left(SO_4\right)_3+6H_2O\)
\(Fe_2\left(SO_4\right)_3+3BaCl_2->3BaSO_4\downarrow+2FeCl_3\)
\(2Fe+3Cl_2\rightarrow\left(t^o\right)2FeCl_3\\ FeCl_3+3KOH\rightarrow Fe\left(OH\right)_3+3KCl\\ 2Fe\left(OH\right)_3\rightarrow\left(t^o\right)Fe_2O_3+3H_2O\\ Fe_2O_3+6HCl\rightarrow2FeCl_3+3H_2O\)
2Fe+3Cl2→(to)2FeCl3
FeCl3+3KOH→Fe(OH)3+3KCl2
Fe(OH)3→(to)Fe2O3+3H2O
Fe2O3+6HCl→2FeCl3+3H2O
4FeS2 + 11O2 -> 8SO2 + 2Fe2O3
2Fe(OH)3 → Fe2O3 + 3H2O
3Fe2O3 + H2 -> 2Fe3O4
FeS + 2HCl → FeCl2 + H2S↑
\(Fe\left(NO_3\right)_3+3KOH\rightarrow3KNO_3+Fe\left(OH\right)_3\downarrow\)
\(2Fe\left(OH\right)_3\xrightarrow[]{t^o}Fe_2O_3+3H_2O\)
\(Fe_2O_3+6HCl\rightarrow2FeCl_3+3H_2O\)
\(2FeCl_3+Fe\rightarrow3FeCl_2\)
\(FeCl_2+\dfrac{1}{2}Cl_2\rightarrow FeCl_3\)
\(FeCl_3+3AgNO_3\rightarrow Fe\left(NO_3\right)_3+3AgCl\downarrow\)
a.
\(\left(1\right)Fe+2HCl--->FeCl_2+H_2\)
\(\left(2\right)FeCl_2+2NaOH--->2NaCl+Fe\left(OH\right)_2\)
\(\left(3\right)4Fe\left(OH\right)_2+O_2+2H_2O\overset{t^o}{--->}4Fe\left(OH\right)_3\)
\(\left(4\right)2Fe\left(OH\right)_3\overset{t^o}{--->}Fe_2O_3+3H_2O\)
\(\left(5\right)Fe_2O_3+6HCl--->2FeCl_3+3H_2O\)
b.
\(\left(1\right)4Al+3O_2\overset{t^o}{--->}2Al_2O_3\)
\(\left(2\right)Al_2O_3+6HCl--->2AlCl_3+3H_2O\)
\(\left(3\right)AlCl_3+3NaOH--->Al\left(OH\right)_3+3NaCl\)
\(\left(4\right)2Al\left(OH\right)_3\overset{t^o}{--->}Al_2O_3+3H_2O\)
\(\left(5\right)Al_2O_3+3H_2SO_4--->Al_2\left(SO_4\right)_3+3H_2O\)
\(b,\left(1\right)4Al+3O_2\rightarrow^{t^o}2Al_2O_3\\ \left(2\right)Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\\ \left(3\right)AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ \left(4\right)2Al\left(OH\right)_3\rightarrow^{t^o}Al_2O_3+3H_2O\\ \left(5\right)Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(a,\left(1\right)Fe+2HCl\rightarrow FeCl_2+H_2\\ \left(2\right)FeCl_2+2NaOH\rightarrow Fe\left(OH\right)_2+2NaCl_2\\ \left(3\right)4Fe\left(OH\right)_2+O_2+2H_2O\rightarrow4Fe\left(OH\right)_3\\ \left(4\right)2Fe\left(OH\right)_3\rightarrow^{t^o}Fe_2O_3+3H_2O\\ \left(5\right)Fe_2O_3+6HCl\rightarrow2FeCl_3+3H_2O\)
Trả lời:
a, PTHH:
Fe + HCl → FeCl2 + H2↑
FeCl2 + Cl2 → FeCl3
FeCl3 + 3 NaOH → Fe(OH)3↓ + 3 NaCl
Fe(OH)3 \(\underrightarrow{t^o}\) Fe2O3 + H2O
Fe2O3 + CO \(\underrightarrow{t^o}\) Fe + CO2↑
CO2 + NaOH → Na2CO3 + H2O
Na2CO3 + BaCl2 → NaCl + BaCO3↓
NaCl + AgNO3 → AgCl↓ + NaNO3
a)Fe+2HCl→FeCl2+H2
2FeCl2+Cl2→2FeCl3
Fe+FeCl3→2FeCl2
FeCl3+3NaOH→Fe(OH)3+3NaCl
2Fe(OH)3→toFe2O3+3H2O
Fe2O3+3CO→2Fe+3CO2
CO2+2NaOH→Na2CO3+H2O
Na2CO3+BaCl2→BaCO3↓+2NaCl
NaCl+AgNO3→AgCl↓+NaNO3
b)FeS+2HCl→FeCl2+H2S
H2S+Cu(OH)2→CuS+2H2O
2CuS+3O2→2CuO+2SO2
SO2+2Mg→2MgO+S
S+O2→SO2