Tìm x
x=102 x 53 x 156 / 36 x 510
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a) x ∈ {-2;-1;;0;1;2;3}
b) x ∈ {10;11;12}
c) x ∈ {0;1;2;3;4;5}
d) x ∈ {-1;0;1;2}
\(\left[3^4-\left(8^2+14\right):13\right]\cdot x=5^3+10^2\)
\(\Rightarrow\left[81-\left(64+14\right):13\right]\cdot x=125+100\)
\(\Rightarrow\left(81-78:13\right)\cdot x=225\)
\(\Rightarrow\left(81-6\right)\cdot x=225\)
\(\Rightarrow75\cdot x=225\)
\(\Rightarrow x=225:75\)
\(\Rightarrow x=3\)
\(\left[{}\begin{matrix}x.36=540\Rightarrow x=540:36\Rightarrow x=15\\2040:x=85\Rightarrow x=2040:85\Rightarrow x=24\\x:53=60\Rightarrow x=60.53\Rightarrow x=3180\end{matrix}\right.\)
x:2=6
x= 6*2
x=12
x.8=88
x=88:8
x=11
x+36=102
x=102-36
x=66
a )\(x:2=6\)
\(x=2\times6=12\)
b ) \(x\times8=88\)
\(x=88:8=11\)
c ) \(x+36=102\)
\(x=102-36=66\)
a) 2x + 36 : 12 = 53
2x + 3 = 53
2x = 53 – 3
2x = 50
x = 25
b) |x + 7| = |- 15|
|x + 7| = 15
x + 7 = 15 hoặc x + 7 = - 15
x = 15 – 7 hoặc x = -15 – 7
x = 8 hoặc x = - 22
c) 19 – | x – 1 | = 4
| x – 1 | = 15
x – 1 = 15 hoặc x – 1 = -15
x = 15 + 1 hoặc x = -15 + 1
x = 16 hoặc x = - 14
a, 71.2 – 6.(2x+5) = 10 5 : 10 3
71.2 – 6.(2x+5) = 10 2
6.(2x+5) = 71.2 – 100
6.(2x+5) = 42
x = 1
b, 5 x + 3 4 . 6 8 = 6 9 . 3 4
5 x + 3 4 . 6 8 = 6 8 . 6 . 3 4
5 x + 3 4 = 6 8 . 6 . 3 4 : 6 8 = 6 . 3 4
5x = 6 . 3 4 - 3 4 = 5 . 3 4
x = 3 4
c, 12:{390:[5. 10 2 – ( 5 3 + x . 7 2 )]} = 4
390:[5. 10 2 – ( 5 3 + x . 7 2 )] = 12:4 = 3
5. 10 2 – ( 5 3 + x . 7 2 ) = 390:3 = 130
5 3 + x . 7 2 = 5. 10 2 – 130 = 370
x . 7 2 = 370 – 5 3 = 245
x = 245: 7 2 = 5
d, 5 3 .(3x+2):13 = 10 3 : 13 5 : 13 4
5 3 .(3x+2):13 = 10 3 : 13
3x+2 = 10 3 : 13 : 5 3 .13 = 8
x = 2
(145 x 99 + 145 ) - ( 143 x 102 – 143 × 2 ) + 54 x 47 - 47 x 53 - 20 - 27
= 145 × (99 + 1) – 143 × (102 – 2) + 47 × (54 – 53) – (20 + 27)
= 145 × 100 – 143 × 100 + 47 × 1 – 47
= 100 × (145 – 143) + (47 – 47)
= 100 × 2 + 0
= 200
= 145 x (99+1) - 143 x ( 102-2) + 47 x ( 54 - 53) -20-27
= 145 x 100 - 143 x 100 + 47 x 1 -20-27
= 100 x ( 145 - 143 ) + 47 - 20 - 27
= 200 + 47 - 20 - 27
= 200