a) 4 . ( x + 3 ) + 3 . ( x - 4 ) = 28
b) 6 . ( x - 4 ) + 3 . ( x + 8 ) = 27
c) 3636 : ( 12x - 91 ) =36
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52-2(3x-6)=10 3636:(12x-91)=36 2x+3=32
2(3x-6)=52-10 12x-91=3636:36 2x=32-3
2(3x-6)=42 12x-91=101 2x=29
3x-6=42:2 12x=101+91 x=29:2 (loại vì x thuộc N)
3x-6=21 12x=192
3x=21+6 x=192:12=16
3x=27
x=27:3=9
2x.8=512 (24-x)3=64
2x=512:8 (24-x)3=43
2x=64 => 24-x=4
x=64:2=32 x=24-4=20
a,52-2(3x-6)=10
2(3x-6)=52-19=42
3x-6=42:2=21
3x=21+6=27
x=27:3
x=9
b,3636:(12x-91)=36
12x-91=3636:36=101
12x=101+91=192
x=192:12
x=16
c,2x+3=32
2x=32-3=29
x=29:2
x=29/2.Vì x thuộc tập số tự nhiên=> không tồn tại x thỏa mãn đề bài
d,2x.8=512
2x=512:8=64
x=64:2
x=32
e,(24-x)^3=64
(24-x)^3=4^3
=>24-x=4
x=24-4
x=20
\(a,\Rightarrow12x-91=101\\ \Rightarrow12x=192\\ \Rightarrow x=16\\ b,\Rightarrow x:23+45=133\\ \Rightarrow x:23=88\\ \Rightarrow x=\dfrac{88}{23}\\ c,\Rightarrow\left(6x-39\right):7=3\\ \Rightarrow6x-39=21\\ \Rightarrow6x=60\\ \Rightarrow x=10\\ d,\Rightarrow3x-24=\dfrac{148}{73}\\ \Rightarrow3x=\dfrac{1900}{73}\\ \Rightarrow x=\dfrac{1900}{219}\\ e,\Rightarrow\left[{}\begin{matrix}x=0\\x=10\end{matrix}\right.\\ f,\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\\ d,\left(9-x\right)^3=64=4^3\\ \Rightarrow9-x=4\\ \Rightarrow x=5\\ h,\Rightarrow x=27\\ i,\Rightarrow6x=312\cdot12=624\cdot6\\ \Rightarrow x=624\\ j,\Rightarrow\left(19x+104\right):14=25-42=-17\\ \Rightarrow19x+104=-238\\ \Rightarrow19x=-342\\ \Rightarrow x=-18\)
a: A=(-x)^3+3*(-x)^2*2+3*(-x)*2^2+2^3=(-x+2)^3
=(28+2)^3=30^3=27000
b: \(C=\left(x+2y-2\right)^3=\left(20+2\cdot9-2\right)^3\)
=36^3
c: 11^3-1
=(11-1)(11^2+11+1)
=10*(121+12)
=1330
d: x^3-y^3=(x-y)^3+3xy(x-y)
=6^3+3*6*9
=216+162
=378
a, \(219-7\left(X+1\right)=100\)
\(\Rightarrow219-7X-7=100\)
\(\Rightarrow7X=219-7-100=112\)
\(\Rightarrow X=112:7=16\)
b,\(\left(3X-6\right)x3=3^4\)
\(\Rightarrow3X-6=81:3=27\)
\(\Rightarrow3X=27+6=33\)
\(\Rightarrow X=33:3=11\)
c,\(3636:\left(12X-91\right)=36\)
\(\Rightarrow12X-91=3636:36=101\)
\(\Rightarrow12X=101+91=192\)
\(\Rightarrow X=192:12=16\)
Đúng luôn nên...hằng ngày k cho mk 3 lần, bao h đủ 100 lần thì tui nhé
\(\Rightarrow12x-91=\dfrac{3636}{36}=101\\ \Rightarrow x=16\)
3636 : (12x - 91) = 36
12x - 91 = 3636 : 36
12x - 91 = 101
12x = 101 + 91
12x = 200
x = 192 : 12 = 16
a. 3636 : (12x - 91) = 36
=> 12x - 91 = 3636 : 36
=> 12x - 91 = 101
=> 12x = 101 + 91
=> 12x = 192
=> x = 192 : 12
=> x = 16
b. (x : 23 + 45). 67 = 8911
=> x : 23 + 45 = 8911 : 67
=> x : 23 + 45 = 133
=> x : 23 = 133 - 45
=> x : 23 = 88
=> x = 88 . 23
=> x = 2024
c. (19x + 2.52) : 14 = (13 - 8)2 - 4
=> (19x + 2.25) : 14 = 52 - 4
=> (19x + 50) : 14 = 25 - 4
=> (19x + 50) : 14 = 21
=> 19x + 50 = 21. 14
=> 19x + 50 = 294
=> 19x = 294 - 50
=> 19x = 244
=> x = 244 : 19
=> x = 244/19 (Xem lại đề)
d. -12 .(x - 5) + 7.(3 - x) = 5
=> -12x + 60 + 21 - 7x = 5
=> -19x + 81 = 5
=> -19x = 5 - 81
=> -19x = -76
=> x = -76 : (-19)
=> x = 4
\(71-\left(33+x\right)=26\)
<=> \(71-33-x=26\)
<=> \(38-x=26\)
<=> \(x=38-26=12\)
\(3636:\left(12x-91\right)=36\)
<=> \(12x-91=101\)
<=> \(12x=192\)
<=> \(x=16\)
\(\left(x-15\right)-218=0\)
<=> \(x-15=218\)
<=> \(x=233\)
\(45+\left(x-6\right).3=81\)
<=> \(\left(x-6\right).3=36\)
<=> \(x-6=12\)
<=> \(x=18\)
\(124x-4x-70x=150\)
<=> \(\left(124-4-70\right).x=150\)
<=> \(50x=150\)
<=> \(x=3\)
1) 71 - ( 33 + x ) = 26
<=> 33 + x = 71 - 26
<=> 33 + x = 45
<=> x = 12
2) 3636 : ( 12x - 91 ) = 36
<=> 12x - 91 = 101
<=> 12x = 192
<=> x = 16
3) ( x - 15 ) - 218 = 0
<=> x - 15 = 218
<=> x = 218 + 15
<=> x = 233
4) 45 + ( x - 6 ) .3 = 81
<=> 45 + ( x - 6 ) = 27
<=> x - 6 = -18
<=> x = -12
5) 124x - 4x - 70x = 150
<=> 5x = 150
<=> x = 150 : 50
<=> x = 3
a) 4(x + 3) + 3(x - 4) = 28
4x + 12 + 3x - 12 = 28
7x = 28
x = 4
b) 6(x - 4) + 3(x + 8) = 27
6x - 24 + 3x + 24 = 27
9x = 27
x = 3
c) 3636 : ( 12x - 91 ) = 36
( 12x - 91 ) = 3636 : 36
12x - 91 = 101
12x = 101 + 91
12x = 192
x = 192 : 12
x = 16