Question

[N.Ngọc Quyết (☆๖ۣۜǤαмєŦV☆) LQ 2k1]

Giải phương trình 

x-241/17 + x-220/19 + x-195/21 + x - 166/23 = 10

Answer 1

[Kudo Shinichi]

\(\frac{x-241}{17}+\frac{x-220}{19}+\frac{x-195}{21}+\frac{x-163}{23}=10\)

\(\Leftrightarrow\frac{x-241}{17}-1+\frac{x-220}{19}-2+\frac{x-195}{21}-3+\frac{x-166}{23}-4=0\)

\(\Leftrightarrow\frac{x-258}{17}+\frac{x-258}{19}+\frac{x-258}{21}+\frac{x-258}{23}=0\)

\(\Leftrightarrow\left(x-258\right)\left(\frac{1}{17}+\frac{1}{19}+\frac{1}{21}+\frac{1}{23}\right)=0\)

\(\Leftrightarrow x=258\)

Vậy \(x=258\)

Chúc bạn học tốt !!!