Tìm số dư của tổng sau khi chia cho 57 :
S=1+7+72+73+74+75+76+77+78.
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\(A=7+7^2+7^3+7^4+7^5+7^6+7^7+7^8\)
\(A=\left(7+7^3\right)+\left(7^2+7^4\right)+\left(7^5+7^7\right)+\left(7^6+7^8\right)\)
\(A=7\cdot\left(7+7^2\right)+7^2\cdot\left(1+7^2\right)+7^5\cdot\left(1+7^2\right)+7^6\cdot\left(1+7^2\right)\)
\(A=7\cdot50+7^2\cdot50+7^5\cdot50+7^6\cdot50\)
\(A=50\cdot\left(7+7^2+7^5+7^6\right)\)
\(A=5\cdot10\cdot\left(7+7^2+7^5+7^6\right)\)
Ta có: 5 ⋮ 5
⇒ \(A=5\cdot10\cdot\left(7+7^2+7^5+7^6\right)\) ⋮ 5 (đpcm)
A = 7 + 72 + 73 + 74 + 75 + 76 + 77 + 78
A = (7 + 73) + (72+ 74) + (75 + 77) + (76 + 78)
A = 7.(1 + 72) + 72.(1 + 72) + 75.(1 + 72) + 76.(1 + 72)
A = 7.( 1 + 49) + 72.( 1 + 49) + 75.(1 + 49) + 76. (1 + 49)
A = 7.50 + 72.50 + 75.50 + 76.50
A = 50.(7 + 72 + 75 + 76)
Vì 50 ⋮ 5 nên A = 50.(7 + 72 + 76) ⋮ 5 đpcm
71 + 72 + 73 + 74 + 75 + 76 + 77 + 78 + 79
= ( 71 + 79 ) + ( 72 + 78 ) + ( 73 + 77 ) + ( 74 + 76 ) + 75
= 150 + 150 + 150 + 150 + 75
= 150 x 4 + 75
= 600 + 75
= 675
Tìm x :
X x 7 + X x 2 = 108
X x ( 7 + 2 ) = 108
X x 9 = 108
X = 108 : 9
X = 12
\(71+72+73+74+75+76+77+78+79\)
\(=\left(71+79\right)+\left(72+78\right)+\left(73+77\right)+\left(74+76\right)+75\)
\(=150+150+150+150+75\)
\(=600+75\)
\(=675\)
\(X\)x\(7+X\)x\(2=108\)
\(X\)x\(\left(7+2\right)=108\)
\(X\)x\(9=108\)
\(X=108:9\)
\(X=12\)
Vậy \(X=12\)
a, A = 1 + 5 3 + 5 5 + 5 7 + . . . + 5 99
B = 5 4 + 5 6 + 5 8 + . . . + 5 100 = 5 . ( 5 3 + 5 5 + 5 7 + . . . + 5 99 ) = 5(A – 1)
A + B – 1 = 5 3 + 5 4 + . . . + 5 100
5(A + B – 1) = 5 4 + 5 5 + . . . + 5 100 + 5 101
4(A + B – 1) = 5(A + B – 1) – (A + B – 1) = 5 101 - 5 3
=> A + B – 1 = 5 101 - 5 3 4
=> A + 5(A – 1) –1 = 5 101 - 5 3 4 => 6A – 6 = 5 101 - 5 3 4
=> A – 1 = 5 101 - 5 3 24
=> A = 5 101 - 5 3 + 24 24
b, A = 1 - 2 + 2 2 - . . . - 2 2007
A = 1 + 2 2 + . . . + 2 2006 - 2 + 2 3 + . . . + 2 2007
A = ( 1 + 2 2 + . . . + 2 2006 ) - 2 . 1 + 2 2 + . . . + 2 2006
A = - 1 + 2 2 + . . . + 2 2006
Đặt B = - 2 + 2 3 + . . . + 2 2007 = - 2 . 1 + 2 2 + . . . + 2 2006 = 2A
A + B = - 1 + 2 + 2 2 + . . . + 2 2006 + 2 2007
2(A+B) = - 2 + 2 2 + . . . + 2 2006 + 2 2007 + 2 2008
A+B = 2(A+B)–(A+B) = - 2 2008 - 1
=> A+2A = - 2 2008 - 1
=> 3A = - 2 2008 - 1
=> A = - ( 2 2008 - 1 ) 3
c, A = 7 + 7 3 + 7 5 + 7 7 + . . . + 7 1999
Đặt B = 7 2 + 7 4 + 7 6 + . . . + 7 1999 + 7 2000 = 7 ( 7 + 7 3 + 7 5 + 7 7 + . . . + 7 1999 ) = 7A
A+B = 7 + 7 2 + 7 3 + . . . + 7 1999 + 7 2000
7(A+B) = 7 2 + 7 3 + . . . + 7 1999 + 7 2000 + 7 2001
7(A+B) – (A+B) = ( 7 2 + 7 3 + . . . + 7 1999 + 7 2000 + 7 2001 ) – ( 7 + 7 2 + 7 3 + . . . + 7 1999 + 7 2000 )
6(A+B) = 7 2001 - 7
A+B = 7 2001 - 7 6
=> A + 7A = 7 2001 - 7 6 => 8A = 7 2001 - 7 6 => A = 7 2001 - 7 48
II. Choose the word whose primary stress position is different from the rest in each line.
1. A. cattle B. country C. canal D. cover
2. A. police B. teacher C. lesson D. future
3. A. apply B. decide C. protect D. cancel
4. A. television B. tradition C. ability D. production
5. A. intelligent B. understand C. biology D. compulsory
I. Choose the best answer among A, B, C or D to complete the sentence. (10 pts)
1. I prefer collecting stamps _______ watching TV.
A. more than B. by C. to D. than
2. “_______ do you go to school every day?” – “On foot.”
A. How often B. How C. Where D. When
Sửa đề: \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)Ta có: \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)
\(\Leftrightarrow\dfrac{74-x}{26}+1+\dfrac{75-x}{25}+1+\dfrac{76-x}{24}+1+\dfrac{77-x}{23}+1+\dfrac{78-x}{22}+1=0\)
\(\Leftrightarrow\dfrac{100-x}{26}+\dfrac{100-x}{25}+\dfrac{100-x}{24}+\dfrac{100-x}{23}+\dfrac{100-x}{22}=0\)
\(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\right)=0\)
mà \(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}>0\)
nên 100-x=0
hay x=100
Vậy: S={100}
Ta có : \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)
\(\Leftrightarrow\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}+5=0\)
\(\Leftrightarrow\dfrac{74-x}{26}+1+\dfrac{75-x}{25}+1+\dfrac{76-x}{24}+1+\dfrac{77-x}{23}+1+\dfrac{78-x}{22}+1=0\)
\(\Leftrightarrow\dfrac{100-x}{26}+\dfrac{100-x}{25}+\dfrac{100-x}{24}+\dfrac{100-x}{23}+\dfrac{100-x}{22}=0\)
\(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\right)=0\)
Thấy : \(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\ne0\)
\(\Rightarrow100-x=0\)
\(\Leftrightarrow x=100\)
Vậy ...