Tính
0,1(6) + 1, ( 3 )
1,(3) + 0,1(2) . \(2\frac{8}{11}\)
0,(6) + 1,(6)
3,(6) + 1,(36) x \(2\frac{1}{5}\)
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\(A=\left(27,54.\frac{11}{16}-3.405\right):3\)
\(A=\left(\frac{15147}{800}-3.405\right):3\)
\(A=\frac{12423}{800}:3\)
\(A=\frac{4141}{800}\)
\(B=\left(\frac{1}{6}+0,1+\frac{1}{5}\right):\left(\frac{1}{6}+0,1-\frac{1}{5}\right)\)
\(B=\frac{7}{15}:\frac{1}{15}\)
\(B=7\)
\(C=\left(0,5-\frac{1}{3}+0,25\right):\left(0,25-\frac{1}{6}\right)\)
\(C=\frac{5}{12}:\frac{1}{12}\)
\(C=5\)
\(D=\frac{13,5.1420+4,5.780.3}{3+6+9+...+24+27}\)
Số số hạng từ 3 đến 27 là:
(27-3):3+1=9(số hạng)
Tổng dãy số từ 3 đến 27 là:
(27+3)x9:2=135
\(D=\frac{13,5.1420+13,5.780}{135}\)
\(D=\frac{13,5.\left(1420+780\right)}{135}\)
\(D=2200\)
c) \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}=\frac{3\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{5\left(0,123-0,1+\frac{1}{11}+\frac{1}{12}\right)}=\frac{3}{5}\)
C = \(25.\left(\frac{-1}{3}\right)^3\) \(+\frac{1}{5}\) \(-2.\left(\frac{-1}{2}\right)^2\) \(-\frac{1}{2}\)
C = \(25.\left(\frac{-1}{27}\right)+\frac{1}{5}\) \(-2.\frac{1}{4}\) \(-\frac{1}{2}\)
C = \(\frac{-25}{27}\) \(+\frac{1}{5}\) \(-\frac{1}{2}\) \(-\frac{1}{2}\)
C = \(\frac{-25}{27}\) \(+\frac{1}{5}\) \(-1\)
C = \(\frac{-125}{135}\) \(+\frac{27}{135}\) \(-\frac{135}{135}\)
C = \(\frac{-233}{135}\)
D = \(-8.\left(\frac{3}{4}-\frac{1}{4}\right):\left(\frac{9}{4}-\frac{7}{6}\right)\)
D = \(-8.\frac{1}{2}\) \(.\frac{12}{13}\)
D = \(-4.\frac{12}{13}\)
D = \(\frac{-48}{13}\)
E = \(5\sqrt{16}\) \(-4\sqrt{9}\) \(+\sqrt{25}\) \(-0,3\sqrt{400}\)
E = \(5.4-4.3+5-0,3.20\)
E = \(20-12+5-6\)
E = \(8+\left(-1\right)\)
E = \(7\)
F = \(\left(\frac{-3}{2}\right)\) \(+\left|\frac{-5}{6}\right|\) \(-1\frac{1}{2}\) \(:6\)
F = \(\left(\frac{-3}{2}\right)\) \(+\frac{5}{6}\) \(-\frac{3}{2}\) \(.\frac{1}{6}\)
F = \(\left(\frac{-3}{2}\right)\) \(+\frac{5}{6}\) \(-\frac{1}{4}\)
F = \(\left(\frac{-18}{12}\right)\) \(+\frac{10}{12}\) \(-\frac{3}{12}\)
F = \(\frac{-11}{12}\)
Chúc cậu hk tốt ~
anh ơi đang kiểm tra anh tự làm đi đừng hỏi anh ạ
em khuyên chân thành để tốt cho anh đấy
\(\frac{\left(\frac{2}{5}+1,15+\frac{-9}{20}\right):0,1}{2\frac{1}{3}+3\frac{1}{6}}=\frac{\left(\frac{2}{5}+\frac{23}{20}+\frac{-9}{20}\right):\frac{1}{10}}{\left(2+3\right)+\left(\frac{1}{3}+\frac{1}{6}\right)}=\frac{\left(\frac{2}{5}+\frac{7}{10}\right):\frac{1}{10}}{5+\frac{1}{2}}\)\(=\frac{\frac{11}{10}:\frac{1}{10}}{\frac{11}{2}}=\frac{11}{\frac{11}{2}}=11:\frac{11}{2}=2\)
a) \({4^6}.\sqrt {0,1} = 1295,2689\)
b) \(\sqrt[8]{{2,{1^{18}} + 1}} - \sqrt {2,{1^{12}} + 1} = - 80,4632\)
c) \(\frac{{1,{5^3}}}{{\sqrt[3]{{6,8}}}} = 1,7814\)
a) 0,16 + 1,3
= \(\frac{4}{25}+\frac{13}{10}\)
= \(\frac{40}{250}+\frac{325}{250}\)
= \(\frac{73}{50}\)
b) 1,3 + 0,12 . \(2\frac{8}{11}\)
= \(\frac{13}{10}+\frac{3}{25}\times\frac{30}{11}\)
= \(\frac{13}{10}+\frac{18}{55}\)
= \(\frac{143}{110}+\frac{36}{110}\)
= \(\frac{179}{110}\)
c) 0,6 + 1,6
= \(\frac{3}{5}+\frac{8}{5}\)
= \(\frac{11}{5}\)
d) 3,6 + 1,36 \(\times\)\(2\frac{1}{5}\)
= \(\frac{18}{5}+\frac{34}{25}\times\frac{11}{5}\)
= \(\frac{18}{5}+\frac{374}{125}\)
= \(\frac{450}{125}+\frac{374}{125}\)
= \(\frac{824}{125}\)