So sánh : 1/6 + 1/12 +1/20 +.................. +1/180 và 0,4
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Ta co:
1/2+1/6+1/12+1/20+1/30+1/42
=1/1.2+1/2.3+1/3.4+1/4.5+1/5.6+1/6.7
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7
=1-1/7
=6/7
Ta co: 6/7=6.10101/7.10101=60606/70707
Vi 60606/70707=60606/70707 nen 6/7=60606/70707
Vay 1/2+1/6+1/12+1/20+1/30+1/42 = 60606/70707
ta có:
\(\frac{60606}{70707}=\frac{6}{7}\)
ta có:
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}=\)
\(1-\frac{1}{2}+\frac{1}{2}-...-\frac{1}{7}=\frac{6}{7}\)
suy ra 6/7=6/7
suy ra \(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}=\frac{60606}{70707}\)
1 nâng lên lũy thừa nào cũng bằng 1, do đó:
\(1^6=1^{12}=1^{20}=1^{30}=1^{40}=1^3\)
\(\Rightarrow A=1+1+1+1+1=5;B=1\)
\(5>1\Rightarrow A>B\)
\(E=\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+...+\dfrac{2}{2256}\)
\(=\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{47.48}\)
\(=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{47}-\dfrac{1}{48}\)
\(=\dfrac{1}{2}-\dfrac{1}{48}\)
\(=\dfrac{23}{48}\)
`A=(20^10+1)/(20^11+1)`
`=>20A=(20^11+20)/(20^11+1)=1+19/(20^11+1)`
Hoàn toàn tương tự: `20B=1+19/(20^12+1)`
Vì `19/(20^12+1)<19/(20^11+1)`
`=>20B<20A`
`=>B<A`