Tính nhan: 6 4/5 - (1 2/3 + 3 4/5)
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Bạn dùng công thức này mà làm nhé :\(\frac{n}{a\times\left(a+n\right)}=\frac{1}{a}-\frac{1}{a+n}\)
Ví dụ :\(\frac{2}{3\times5}=\frac{1}{3}-\frac{1}{5};\frac{3}{4\times7}=\frac{1}{4}-\frac{1}{7};\frac{5}{6\times11}=\frac{1}{6}-\frac{1}{11}\)
a/\(-\dfrac{1}{6}+\left(-\dfrac{5}{8}+\dfrac{7}{6}\right)\)
\(=\left(-\dfrac{1}{6}+\dfrac{7}{6}\right)-\dfrac{5}{8}\)
\(=1-\dfrac{5}{8}\)
\(=\dfrac{8}{8}-\dfrac{5}{8}=\dfrac{3}{8}\)
b/\(\left(\dfrac{2}{5}\right)^2+5\dfrac{1}{2}\cdot\left(4,5-2\right)+\dfrac{2^3}{\left(-4\right)}\)
\(=\dfrac{4}{25}+\dfrac{11}{2}\cdot\dfrac{5}{2}+-\dfrac{2^3}{2^2}\)
\(=\dfrac{4}{25}+\dfrac{55}{4}+\left(-2\right)\)
\(=\dfrac{16}{100}+\dfrac{1375}{100}-\dfrac{200}{100}\)
\(=\dfrac{1191}{100}=11,91\)
\(=\frac{1}{5}\times\frac{1}{3}\times\frac{3}{7}\times\frac{1}{2}\)
\(=\left(\frac{1}{5}\times\frac{1}{2}\right)\times\left(\frac{1}{3}\times\frac{3}{7}\right)\)
\(=\frac{1}{10}\times\frac{1}{7}\)
\(=\frac{1}{70}\)
\(\frac{7}{3}+\frac{13}{3}=\frac{7+13}{3}=\frac{20}{3}\)
\(\dfrac{7}{12}+\dfrac{4}{9}+\dfrac{1}{3}+\dfrac{5}{12}+2=\dfrac{7+5}{12}+\dfrac{4+3}{9}+2=1+\dfrac{7}{9}+2=3+\dfrac{7}{9}=\dfrac{34}{9}\)
\(\dfrac{6}{5}.\dfrac{3}{8}.\dfrac{5}{8}.\dfrac{6}{5}-\dfrac{4}{5}=\dfrac{6.3.5.6}{5.8.8.5}-\dfrac{4}{5}=\dfrac{27}{80}-\dfrac{4}{5}=-\dfrac{37}{80}\)
\(6\frac{4}{5}-\left(1\frac{2}{3}+3\frac{4}{5}\right)\)
\(=\frac{34}{5}-\left(\frac{5}{3}+\frac{19}{5}\right)\)
\(=\frac{34}{5}-\frac{82}{15}\)
\(=\frac{102}{15}-\frac{82}{15}\)
\(=\frac{4}{3}\)
\(6\frac{4}{5}-\left(1\frac{2}{3}+3\frac{4}{5}\right)=\)\(6\frac{4}{5}-1\frac{2}{3}-3\frac{4}{5}\)
\(6+\frac{4}{5}-1-\frac{2}{3}-3-\frac{4}{5}\)
\(\left(6-1-3\right)+\left(\frac{4}{5}-\frac{4}{5}\right)-\frac{2}{3}\)
\(2+0-\frac{2}{3}=2-\frac{2}{3}=\frac{4}{3}\)