3+x/5+ý=3/5vaf x+ý=16
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Tra loi: Vi x+3/y+5 = 3/5
=>(x+3).5 = (y+5) .3
=>5x+15=3y+15
=>5x=3y
=>x=3k;y=5k( k thuoc Z; k khac 0)
Ma x+y=16=> 3k+5k=16
=> k=2
=> x= 3 .2 =6 ;y=2.5=10
Vay x=6 va y+10
\(\frac{x}{3}=\frac{7}{y}\)
\(\Rightarrow x.y=7.3\)
\(\Rightarrow x.y=21\)
\(\Rightarrow x.y=21=7.3=3.7=-7.\left(-3\right)=-3.\left(-7\right)\)
\(\Leftrightarrow x\in\left\{3;7;-3;-7\right\}\)
\(\Leftrightarrow y\in\left\{3;7;-3;-7\right\}\)
sửa vì bài này cần thêm điều kiện x,y thuôc z
\(\frac{x}{3}=\frac{7}{y}\)
\(xy=21\)
do x,y thuộc z
\(x;y\in\left\{\left(1;21\right);\left(21;1\right);\left(-1;-21\right);\left(-21;-1\right);\left(-3;-7\right)\right\}\)còn nữa (3;7);(7;3);(-7;-3)
Giải:
a) \(\dfrac{-5}{8}=\dfrac{x}{16}\)
\(\Rightarrow x=\dfrac{16.-5}{8}=-10\)
\(\dfrac{3x}{9}=\dfrac{2}{6}\)
\(\Rightarrow3x=\dfrac{2.9}{6}=3\)
\(\Rightarrow x=1\)
b) \(\dfrac{x+3}{15}=\dfrac{1}{3}\)
\(\Rightarrow x+3=\dfrac{1.15}{3}=5\)
\(\Rightarrow x=2\)
\(\dfrac{6}{2x+1}=\dfrac{2}{7}\)
\(\Rightarrow2x+1=\dfrac{6.7}{2}=21\)
\(\Rightarrow x=10\)
c) \(\dfrac{4}{x-6}=\dfrac{y}{24}=\dfrac{-12}{18}\)
\(\Rightarrow\dfrac{4}{x-6}=\dfrac{-12}{18}\)
\(\Rightarrow x-6=\dfrac{18.4}{-12}=-6\)
\(\Rightarrow x=0\)
\(\Rightarrow\dfrac{y}{24}=\dfrac{-12}{18}\)
\(\Rightarrow y=\dfrac{-12.24}{18}=-16\)
\(\dfrac{3-x}{-12}=\dfrac{16}{y+1}=\dfrac{192}{-72}\)
\(\Rightarrow\dfrac{3-x}{-12}=\dfrac{192}{-72}\)
\(\Rightarrow3-x=\dfrac{192.-12}{-72}=32\)
\(\Rightarrow x=-29\)
\(\Rightarrow\dfrac{16}{y+1}=\dfrac{192}{-72}\)
\(\Rightarrow y+1=\dfrac{16.-72}{192}=-6\)
d) \(\dfrac{-2}{3}< \dfrac{x}{5}< \dfrac{-1}{6}\)
\(\Rightarrow\dfrac{-20}{30}< \dfrac{6x}{30}< \dfrac{-5}{30}\)
\(\Rightarrow6x\in\left\{-18;-12;-6\right\}\)
\(\Rightarrow x\in\left\{-3;-2;-1\right\}\)
\(\dfrac{-1}{5}\le\dfrac{x}{8}\le\dfrac{1}{4}\)
\(\Rightarrow\dfrac{-8}{40}\le\dfrac{5x}{40}\le\dfrac{10}{40}\)
\(\Rightarrow5x\in\left\{-5;0;5;10\right\}\)
\(\Rightarrow x\in\left\{-1;0;1;2\right\}\)
e) \(\dfrac{x+46}{20}=x\dfrac{2}{5}\)
\(\Rightarrow\dfrac{x+46}{20}=x+\dfrac{2}{5}\)
\(\Rightarrow\dfrac{x+46}{20}=\dfrac{5x+2}{5}\)
\(\Rightarrow5.\left(x+46\right)=20.\left(5x+2\right)\)
\(\Rightarrow5x+230=100x+40\)
\(\Rightarrow5x-100x=40-230\)
\(\Rightarrow-95x=-190\)
\(\Rightarrow x=-190:-95\)
\(\Rightarrow x=2\)
\(y\dfrac{5}{y}=\dfrac{86}{y}\)
\(\Rightarrow y+\dfrac{5}{y}=\dfrac{86}{y}\)
\(\Rightarrow\dfrac{y^2+5}{y}=\dfrac{86}{y}\)
\(\Rightarrow y^2+5=86\)
\(\Rightarrow y^2=86-5\)
\(\Rightarrow y^2=81\)
\(\Rightarrow\left[{}\begin{matrix}y=9\\y=-9\end{matrix}\right.\)
Chúc bạn học tốt!
a 180 -(x + 15) : 4 =80:5 180 - (x + 15) : 4 = 16 180 - ( x + 15) = 16 x 4 180 - ( x + 15 ) = 64 x + 15 = 180 - 64 x + 15 = 116 x= 116 - 15 x = 101
TA CÓ: \(\frac{3+x}{5+y}=\frac{3}{5}\)và \(x+y=16\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\frac{3+x}{5+y}=\frac{3}{5}\Leftrightarrow\frac{3+x}{3}=\frac{5+y}{5}=\frac{3+x+y+5}{3+5}=\frac{24}{8}=3\)
\(\Rightarrow\hept{\begin{cases}\frac{3+x}{3}=3\Leftrightarrow3+x=9\Leftrightarrow x=6\\\frac{5+y}{5}=3\Leftrightarrow5+y=15\Leftrightarrow y=10\end{cases}}\)
Vậy \(x=6\)và \(y=10\)