\(\dfrac{x + 11}{14 - x} = \dfrac{2}{3}\)
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23 tháng 2 2022
a, \(\dfrac{1}{3}+\dfrac{2}{3}:x=-7\) b, \(\left(\dfrac{9}{2}-2x\right).\dfrac{11}{7}=\dfrac{11}{14}\)
\(\dfrac{2}{3}:x=\left(-7\right)-\dfrac{1}{3}\) \(\dfrac{9}{2}-2x\) \(=\dfrac{11}{14}:\dfrac{11}{7}\)
\(\dfrac{2}{3}:x=-\dfrac{22}{3}\) \(\dfrac{9}{2}-2x\) \(=\dfrac{1}{2}\)
\(x=\dfrac{2}{3}.\left(-\dfrac{22}{3}\right)\) \(2x\) \(=\dfrac{9}{2}-\dfrac{1}{2}\)
\(x=-\dfrac{1}{11}\) \(2x\) \(=4\)
\(x\) \(=4:2\)
\(x\) \(=2\)
24 tháng 6 2021
`5/7xx5/11+5/7xx2/11-5/7xx14/11`
`=5/7xx(5/11+2/11-14/11)`
`=5/7xx(-7/11)`
`=-5/11`
NT
Nguyễn Tuấn Tú
CTVHS
12 tháng 3 2023
5/2 - 1/4 + 5/3
= 10/4 - 1/4 + 5/3
= 9/4 + 5/3
= 27/12 + 20/12
= 47/12
11/2 : 1/4 x 5/3
= 11/2 x 4/1 x 5/3
= 44/2 x 5/3
= 220/6
= 110/3
14/5 x 2/3 + 5
= 28/15 + 5
= 28/15 + 75/15
= 103/15
11 tháng 3 2023
f: =>\(\dfrac{14}{3\left(x-4\right)}-\dfrac{x+2}{x-4}=\dfrac{-3}{2\left(x-4\right)}-\dfrac{5}{6}\)
=>28-6(x+2)=-9-5(x-4)
=>28-6x-12=-9-5x+20
=>-6x+16=-5x+11
=>-x=-5
=>x=5
12 tháng 3 2023
d: =>\(\dfrac{12x+1}{11x-4}=\dfrac{20x+17-20x+8}{18}=\dfrac{25}{18}\)
=>25(11x-4)=18(12x+1)
=>275x-100=216x+18
=>59x=118
=>x=2
f: =>\(\dfrac{14}{3\left(x-4\right)}-\dfrac{x+2}{x-4}=\dfrac{-3}{2\left(x-4\right)}-\dfrac{5}{6}\)
=>28-6(x+2)=-9-5(x-4)
=>28-6x-12=-9-5x+20
=>-6x+16=-5x+11
=>-x=-5
=>x=5
Y
17 tháng 1 2023
\(1,\left(dk:x\ne0,-1,4\right)\)
\(\Leftrightarrow\dfrac{9}{x+1}+\dfrac{2}{x-4}-\dfrac{11}{x}=0\)
\(\Leftrightarrow\dfrac{9x\left(x-4\right)+2x\left(x+1\right)-11\left(x+1\right)\left(x-4\right)}{x\left(x+1\right)\left(x-4\right)}=0\)
\(\Leftrightarrow9x^2-36x+2x^2+2x-11x^2+44x-11x+44=0\)
\(\Leftrightarrow-x=-44\)
\(\Leftrightarrow x=44\left(tm\right)\)
\(2,\left(đk:x\ne4\right)\)
\(\Leftrightarrow\dfrac{14}{3\left(x-4\right)}-\dfrac{2+x}{x-4}-\dfrac{3}{2\left(x-4\right)}+\dfrac{5}{6}=0\)
\(\Leftrightarrow\dfrac{14.2-6\left(2+x\right)-3.3+5\left(x-4\right)}{6\left(x-4\right)}=0\)
\(\Leftrightarrow28-12-6x-9+5x-20=0\)
\(\Leftrightarrow-x=13\)
\(\Leftrightarrow x=-13\left(tm\right)\)
\(\dfrac{x+11}{14-x}=\dfrac{2}{3}\)
\(\Rightarrow3\left(x+11\right)=2\left(14-x\right)\)
\(\Rightarrow3x+33=28-2x\)
\(\Rightarrow5x=-5\Rightarrow x=-1\)
(14 - x)2 = (x + 11)3
28 - 2x = 3x + 33
28 - 2x - 3x - 33 = 0
- 5 - 5x = 0
x = -1