tìm x biết
\(\frac{-5}{3}< \frac{7}{6}-\left(x-1\right)\le\frac{11}{12}\)
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EC
8 tháng 9 2016
Câu 1:
a)\(\frac{3}{4}-0,25-\left[\frac{7}{3}+\left(-\frac{9}{2}\right)\right]-\frac{5}{6}\)
\(=\frac{3}{4}-\frac{1}{4}-\frac{14}{6}+\frac{27}{6}-\frac{5}{6}\)
\(=\frac{1}{2}-\frac{4}{3}\)
\(=-\frac{5}{6}\)
b)\(7+\left(\frac{7}{12}-\frac{1}{2}+3\right)-\left(\frac{1}{12}+5\right)\)
\(=7+\frac{1}{12}+3-\frac{1}{12}-5\)
\(=5\)
EC
8 tháng 9 2016
Câu 2:
\(\frac{3}{4}-\frac{5}{6}\le\frac{x}{12}< 1-\left(\frac{2}{3}-\frac{1}{4}\right)\)
\(-\frac{1}{12}\le\frac{x}{12}< 1-\frac{5}{12}\)
\(-\frac{1}{12}\le\frac{x}{12}< \frac{7}{12}\)
Vậy -1\(\le\)x<7
2 tháng 2 2022
\(\Leftrightarrow\dfrac{46}{7}+\dfrac{81}{35}< =x< =\dfrac{49}{36}\)
\(\Leftrightarrow\dfrac{311}{35}< =x< =\dfrac{49}{36}\)
\(\Leftrightarrow x\in\varnothing\)
30 tháng 3 2020
\(\frac{3}{7}\cdot15\cdot\frac{1}{3}+\frac{3}{7}\cdot5\cdot\frac{2}{5}\le x\le\left(3\frac{1}{2}:7-6\frac{1}{2}\right)\cdot\left(-2\frac{1}{3}\right)\)
\(\Leftrightarrow\frac{15}{7}+\frac{6}{7}\le x\le-6\cdot\frac{-5}{3}\)
\(\Leftrightarrow3\le x\le10\)
Mà \(x\in Z\)
\(\Rightarrow x\in\left\{4;5;6;7;8;9\right\}\)
HL
17 tháng 8 2017
a)Ta có: 1/2-(1/3+1/4)= -1/12
1/48-(1/16-1/6)=1/8
suy ra: -1/12<x<1/8
<=> -2/24<x<3/24
=>x thuộc:(-1/24 ;0 ;1/24 ;2/24 ;3/24)
B
2 tháng 4 2019
1)
a)
\(\frac{-5}{6}.\frac{120}{25}< x< \frac{-7}{15}.\frac{9}{14}\)
\(\frac{-1}{1}.\frac{20}{5}< x< \frac{-1}{5}.\frac{3}{2}\)
\(\frac{-20}{5}< x< \frac{-3}{10}\)
\(\frac{-40}{10}< x< \frac{-3}{10}\)
\(\Rightarrow Z\in\left\{-4;-5;-6;-7;-8;-9;-10;...;-39\right\}\)
\(\frac{-5}{3}< \frac{7}{6}-\left(x-1\right)\le\frac{11}{12}\)
\(\Leftrightarrow\frac{-20}{12}< \frac{14}{12}-\frac{12\left(x-1\right)}{12}\le\frac{11}{12}\)
\(\Leftrightarrow-20< 14-12\left(x-1\right)\le11\)
\(\Leftrightarrow-20< 14-12x+12\le11\)
\(\Leftrightarrow-20< 26-12x\le11\)
\(\Leftrightarrow26-46< 26-12x\le26-15\)
\(\Leftrightarrow-46< 12x\le-15\)
\(\Leftrightarrow x\in\left\{2;3\right\}\)
Vậy x = 2 hoặc x = 3
ta có:\(\frac{-5}{3}\)<\(\frac{7}{6}\)-(x-1)<=\(\frac{11}{12}\)
=>\(\frac{-20}{12}\)<\(\frac{14}{12}\)-(x-1)<=\(\frac{11}{12}\)
=>\(\frac{-20}{12}\)<\(\frac{14}{12}\)-x+1<=\(\frac{11}{12}\)
=>\(\frac{-20}{12}\)<\(\frac{26}{12}\)-x<=\(\frac{11}{12}\)
=>\(\frac{26}{12}\)-x={-19/12,-18.12,-17/12......,11/12}
=>x={45/12,44/12,43/12........15/12}
=>x={45/12,22/6,43/12......5/4}
Vậy.............................
mik nghĩ zậy!!!!!