Tìm số tự nhiên x biết:
a) 219–7(x+1)=100
b) (3x−6).3=34
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a)
<=> 219 - 7x - 7 = 100
<=> -7x = 100 - 219 + 7
<=> -7x = -112
<=> x = -112 : (-7)
<=> x = 16
b)
<=> 9x - 18 = 34
<=> 9x = 34 + 18
<=> 9x = 52
<=> x = 52 : 9
<=> x = 52/9
a)219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1 =119:7
x+1 =17
x =17-1
x =16
b) (3x-6).3=34
3x-6 =34:3
3x-6 =\(\frac{34}{3}\)
3x =\(\frac{34}{3}\)- 6
3x =\(\frac{16}{3}\)
x =\(\frac{16}{3}\): 3
x =\(\frac{16}{9}\)
a)219-7(x+1)=100
7(x+1)=219-100
x+1=119/7
x+1=17
x=17-1
x=16
b)(3x-6)*3=64
3x-6=64/3
3x=64/3+6
3x=82/3
x=82/3:3
x=82/9
a) 219-7(x+1)=100
219-7x-7=100
-7x=100-219+7
-7x=-112
x=16
b) (3x-6).3=64
3x-6=64/3
3x=82/3
x=82/9
a)219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1=119:7
x+1=17
x=17-1
x=16
b)(3x-6).3=34
(3x-6).3=81
3x-6=81:3
3x-6=17
3x=27+6
3x=33
x=33:3
x=11
li-ke cho mình nha Duong Thi Hoai My
a. 219 - 7(x+1) = 100
7(x+1)=119
x+1=119:7
x+1=17
x=16
Vậy x=16
b. (3x - 6) . 3 = 34
3x-6=34:3
3x-6=33
3x=33
x=11
Vậy x=11
a) \(219-7\left(x+1\right)=100\)
\(\Leftrightarrow219-7x-7=100\)
\(\Leftrightarrow-7x=100-219+7=-112\)
\(\Leftrightarrow x=16\)
b) \(\left(3x-6\right)\cdot3=3^4\)
\(\Leftrightarrow\left(x-2\right)\cdot3^2=3^4\)
\(\Leftrightarrow x-2=3^2\)
\(\Leftrightarrow x=9+2=11\)
a)
\(219-7\left(x+1\right)=100\)
\(\Rightarrow7\left(x+1\right)=119\)
\(\Rightarrow x+1=17\)
=> x = 16
Vậy x = 16
b)
\(\left(3x-6\right)3=3^4\)
\(\Rightarrow\left(x-2\right)3^2=3^4\)
=> x - 2 = 9
=> x = 7
Vậy x = 7
a) 219 - 7 (x + 1) = 100
7 ( x + 1)= 219 -100
7 ( x+ 1) =119
x+1=119 : 7
x+1=17
x=17-1
x= 16
a) 219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1=119:7
x+1=17
=> x = 16
b)(3x-6).3 = 3^4
(3x-6).3 = 81
3x-6= 81:3
3x-6= 27
3x = 27-6
3x=21
=> x= 7.
kik nha
a) 219 - 7(x + 1) = 100 <=> 7(x+1) = 219 - 100
<=> 7(x+1) = 119 <=> x + 1 = 119 : 7 <=> x + 1 = 17
a) 219−7(x+1)=100
- 7(x+ 1)= 100 - 219
- 7(x+ 1)= - 119
x+1 = -119 : (-7)
x+1 = 17
x= 17-1
x= 16
b) (3x - 6). 3 = 34
(3x - 6). 3 = 81
(3x - 6)= 81: 3
(3x - 6)= 27
3x= 27+ 6
3x= 33
x= 33:3
x= 11
b) (3x−6).3=34
a. 219-7(x+1)=100
=> 7(x+1)=219-100
=> 7(x+1)=119
=> x+1=119:7
=> x+1=17
=> x=17-1
=> x=16
b. (3x-6).3=34
=> 3x-6=34:3
=> 3x-6=33
=> 3x-6=27
=> 3x=27+6
=> 3x=33
=> x=33:3
=> x=11
a) => 7.(x + 1) = 119
=> x + 1 = 17
=> x = 16
b) => 3x - 6 = 33
=> 3x = 33
=> x = 11
\(a,2019-7\left(x+1\right)=100\)
=>\(7\left(x+1\right)=2019-100=1919\)
( đến đoạn này có 2 cách làm , bạn thích chọn cách nào thì làm nha ! )
=>\(\left[{}\begin{matrix}x+1=1919:7\\7x+7=1919\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}x+1=\frac{1919}{7}\\7x=1919-7=1912\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=\frac{1919}{7}-1=\frac{1912}{7}\\x=\frac{1912}{7}\end{matrix}\right.\)
Vậy x ∈ {\(\frac{1912}{7}\)}
\(b,\left(3x-6\right).3=34\)
=>\(3x-6=\frac{34}{3}\)
=>\(3x=\frac{34}{3}+6=\frac{52}{3}\)
=> \(x=\frac{52}{3}:3=\frac{52}{9}\)
Vậy x ∈ {\(\frac{52}{9}\)}