1 + 1 = ?
2 + 2 = ?
30 + 20 = ?
10 x 10 = ?
~ Help me :))))) ~
#JH
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\(x\)\(\times\)( \(x\) + 1) = 2 + 4 + 6 + 8 + 10 + 20
\(x\) \(\times\)(\(x\) + 1) = 50
\(x\) \(\times\)(\(x+1\)) = 2 \(\times\) 5 \(\times\) 5
Nếu \(x\) là số tự nhiên thì không tồn tại
Nếu \(x\) là số thực thì câu hỏi này không phù hợp lớp 5 em nhá
Sửa đề
\(\dfrac{2}{1^2}\cdot\dfrac{6}{2^2}\cdot\dfrac{12}{3^3}\cdot.......\cdot\dfrac{110}{10^2}\cdot x=-20\)
\(\dfrac{2}{1\cdot1}\cdot\dfrac{2\cdot3}{2\cdot2}\cdot\cdot\cdot\cdot\dfrac{11\cdot10}{10\cdot10}\cdot x=-20\)
\(\dfrac{\left(2\cdot3\cdot4\cdot....\cdot11\right)}{\left(1\cdot2\cdot3\cdot4\cdot...\cdot10\right)}\cdot\dfrac{\left(1\cdot2\cdot3\cdot4\cdot5\cdot...\cdot10\right)}{\left(1\cdot2\cdot3\cdot4\cdot...\cdot10\right)}\cdot x=-20\)
\(11\cdot x=-20\\ x=-\dfrac{20}{11}\)
a: \(\Leftrightarrow\dfrac{1}{x+2}-\dfrac{1}{x+5}+\dfrac{1}{x+5}-\dfrac{1}{x+10}+\dfrac{1}{x+10}-\dfrac{1}{x+17}=\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)
=>\(\dfrac{x+17-x-2}{\left(x+2\right)\left(x+17\right)}=\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)
=>x=15
b: \(\Leftrightarrow-\dfrac{1}{x-1}+\dfrac{1}{x-3}-\dfrac{1}{x-3}+\dfrac{1}{x-8}-\dfrac{1}{x-8}+\dfrac{1}{x-20}-\dfrac{1}{x-20}=\dfrac{-3}{4}\)
=>1/x-1=3/4
=>x-1=4/3
=>x=7/3
a/ Ta luôn có : \(\begin{cases}x^2\ge0\\\left(y-\frac{1}{10}\right)^4\ge0\end{cases}\)\(\Rightarrow x^2+\left(y-\frac{1}{10}\right)^4\ge0\)
Để dấu "=" xảy ra thì x = 0 , y = 1/10
b/ Tương tự.
Hướng dẫn giải:
a) 3 x (20 – 5)
Cách 1:
3 x (20 – 5) = 3 x 15 = 45
Cách 2:
3 x (20 – 5) = 3 x 20 – 3 x 5 = 60 – 15 = 45
b) 20 x (40 – 1)
Cách 1:
20 x (40 – 1) = 20 x 39 = 780
Cách 2:
20 x (40 – 1) = 20 x 40 – 20 x 1 = 800 – 20 = 780
a) 17.81+19.17-150=17(81+19)-150
=17.100-150
=1700-150=1550
b) 20-[50-(5-1)2 ]=20-[50-42 ]
=20-[50-16]
=20-34=-14
c) 44+7x=103:10
44+7x=102
44+7x=100
7x=100-44
7x=56
x=56:7
x=8
Vậy x=8.
d) |x-1|+3=5
|x-1|=5-3
|x-1|=2
\(\Rightarrow\orbr{\begin{cases}x-1=2\\x-1=-2\end{cases}\Rightarrow\orbr{\begin{cases}x=3\\x=-1\end{cases}}}\)
Vậy x\(\in\){-1;3}
Vì a\(⋮\)9 nên a\(\in\)B(9)={0;9;18;27;36;...}
\(\dfrac{1}{5}\times x-\dfrac{2}{3}=\dfrac{1}{10}\times x+\dfrac{5}{6}\)
\(\dfrac{1}{5}x-\dfrac{2}{3}-\dfrac{1}{10}x-\dfrac{5}{6}=0\)
\(\dfrac{1}{5}x-\dfrac{1}{10}x-\dfrac{2}{3}-\dfrac{5}{6}=0\)
\(\dfrac{1}{10}x-\dfrac{3}{2}=0\)
\(\dfrac{1}{10}x=\dfrac{3}{2}\)
\(x=15\)
\(\dfrac{1}{5}\).x - \(\dfrac{2}{3}\) = \(\dfrac{1}{10}\).x + \(\dfrac{5}{6}\)
⇒ \(\dfrac{1}{5}\).x - \(\dfrac{1}{10}\).x = \(\dfrac{5}{6}\) + \(\dfrac{2}{3}\)
⇒ \(\dfrac{2}{10}\).x - \(\dfrac{1}{10}\).x = \(\dfrac{5}{6}\) + \(\dfrac{4}{6}\)
⇒ \(\dfrac{1}{10}\).x = \(\dfrac{9}{6}\)
⇒ x = \(\dfrac{9}{6}\) : \(\dfrac{1}{10}\)
⇒ x = \(\dfrac{9}{6}\) . 10
⇒ x = \(\dfrac{90}{6}\)
⇒ x = 15
Vậy x = 15
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{x}=\frac{1}{42}\)
\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-......+\frac{1}{5}-\frac{1}{6}+\frac{1}{x}=\frac{1}{42}\)
\(1-\frac{1}{6}+\frac{1}{x}=\frac{1}{42}\)
\(\frac{5}{6}+\frac{1}{x}=\frac{1}{42}\)
\(\frac{1}{x}=\frac{1}{42}-\frac{5}{6}\)
\(\frac{1}{x}=\frac{-34}{42}\)
x=\(\frac{-21}{17}\)
1 + 1 = 2
2 + 2 = 4
30 + 20 = 50
10 x 10 = 100
mk nhanh nhất nè tk mk đi nha
=2
=4
=50
=1000
#Chúc bạn hok tốt
#SABER