1/3. (3x - 2) + 25% = -9/6
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Bài 1:
8: \(=\dfrac{x+3}{x\left(x-3\right)}\)
9: \(=\dfrac{x-2}{x-5}\cdot\dfrac{\left(x-5\right)\left(x+5\right)}{\left(x-2\right)^2}=\dfrac{x+5}{x-2}\)
10: \(=1:\dfrac{a-1}{a}=\dfrac{a}{a-1}\)
12: \(=\dfrac{6\left(x+1\right)}{3x\left(x+1\right)}=\dfrac{2}{x}\)
13: \(\dfrac{3}{x+3}-\dfrac{x-6}{x\left(x+3\right)}\)
\(=\dfrac{3x-x+6}{x\left(x+3\right)}=\dfrac{2x+6}{x\left(x+3\right)}=\dfrac{2}{x}\)
tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0
Toán lớp 6Tìm x
Trả lời Câu hỏi tương tự
Chưa có ai trả lời câu hỏi này,bạn hãy là người đâu tiên giúp nguyenvanhoang giải bài toán này !
a/ 2x\(^{^{ }3}\)-3\(^{^{ }3}\)-2x\(^3\)-1\(^{^{ }3}\)=-28
b/x\(^{^{ }3}\)+2\(^{^{ }3}\)-x\(^3\)+2=10
c/3x\(^3\)+5\(^3\)-3x(3x\(^2\)-1)=3x\(^3\)+5\(^3\)-3x\(^3\)+3x=125+3x
d/ x\(^6\)-(x\(^3\)+1)(x\(^2\)-x+1)= x\(^6\)-(x\(^6\)-x\(^4\)+x\(^3\)+x\(^2\)-x+1)=x\(^4\)-x\(^3\)-x\(^2\)+x-1
\(\frac{1}{3}\left(3x-2\right)+25\%x=\frac{-9}{6}\)
\(\Rightarrow x-\frac{2}{3}+\frac{1}{4}x=\frac{-9}{6}\)
\(\Rightarrow\frac{5}{4}x-\frac{2}{3}=\frac{-9}{6}\)
\(\Rightarrow\frac{5}{4}x=\frac{-5}{6}\)
\(\Rightarrow x=\frac{-3}{2}\)
1) 2(3x+5)-6=9
2(3x+5) =9+6
2(3x+5) =15
3x+5 = 15:2
3x+5 = \(\frac{15}{2}\)
3x = \(\frac{15}{2}-5\)
3x =\(\frac{5}{2}\)
x = \(\frac{5}{2}:3\)
x = \(\frac{5}{6}\)
2) 5x+3(4+2x)=25
5x+12+6x=25
5x+6x =-12+25
11x =13
x =13:11
x =\(\frac{13}{11}\)
3) 3(4x+1)+2(x-1)=105
12x+3+2x-2=105
12x+2x = -3+2+105
14x =104
x = 104:14
x = \(\frac{52}{7}\)
4) \(30-[2\left(x-3\right)-2]=14\)
\(2\left(x-3\right)-2\)=\(30-14\)
\(2\left(x-3\right)-2=16\)
\(2\left(x-3\right)=16+2\)
\(2\left(x-3\right)=18\)
\(x-3=18:2\)
\(x-3=9\)
\(x=9+3\)
\(x=12\)
k mình nha !!!!!!
1/3 . ( 3x - 2 ) + 25% = -9/6
1/3 . ( 3x - 2 ) + 1/4 = -9/6
1/3 . ( 3x - 2 ) = -9/6 - 1/4
1/3 . ( 3x - 2 ) = -2
3x - 2 = -2 : 1/3
3x - 2 = -6
3x = -6 + 2
3x = -4
x = 4/3
Vậy...
#Louis
\(\frac{1}{3}.\left(3x-2\right) +25\%=-\frac{9}{6}\)
\(\frac{1}{3}.\left(3x-2\right)-\frac{1}{4}=-\frac{3}{2}\)
\(\frac{1}{3}.\left(3x-2\right)=-\frac{3}{2}+\frac{1}{4}\)
\(\frac{1}{3}.\left(3x-2\right)=-\frac{5}{4}\)
\(3x-2=-\frac{5}{4}:\frac{1}{3}\)
\(3x-2=-\frac{15}{4}\)
\(3x=-\frac{15}{4}+2\)
\(3x=-\frac{15}{4}+\frac{8}{4}\)
\(3x=-\frac{7}{4}\)
\(x=-\frac{7}{4}:3\)
\(x=-\frac{7}{12}\)