Tìm x
A. 3/5.(3/2 - x) = -0.3
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\(\frac{5}{3}:\frac{x}{4}=6:0,3\)
\(\frac{20}{3x}=20\)
\(3x=1\)
\(x=\frac{1}{3}\)
Vậy \(x=\frac{1}{3}\)
\(\frac{4}{5}x-\frac{4}{3}\left(x-\frac{1}{4}\right)=0,3+\left(-\frac{1}{3}\right)^2\)
\(\Rightarrow\frac{4}{5}x-\frac{4}{3}x+\frac{1}{3}=0,3+\frac{1}{9}\)
\(\Rightarrow\frac{-8}{15}x+\frac{1}{3}=\frac{37}{90}\)
\(\Rightarrow-\frac{8}{15}x=\frac{7}{90}\)
\(\Rightarrow x=-\frac{7}{48}\)
a) \(\Rightarrow x^2+4x+25-x^2=3\Rightarrow4x=-22\Rightarrow x=-\dfrac{11}{2}\)
b) \(\Rightarrow\left(4x+3-2x+3\right)\left(4x+3+2x-3\right)=0\)
\(\Rightarrow2\left(x+3\right).6x=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)
a: =>1/2:x=-3/10
hay x=1/2:(-3/10)=-5/3
b: =>1/5(2-x)=6/5
=>2-x=6
hay x=-4
\(a,x=\dfrac{1}{2}-\dfrac{2}{5}\)
\(x=\dfrac{1}{10}\)
\(b,x+\dfrac{3}{7}=\dfrac{7}{10}\)
\(x=\dfrac{7}{10}-\dfrac{3}{7}\)
\(x=\dfrac{19}{70}\)
\(c,19-x=\dfrac{17}{20}\)
\(x=19-\dfrac{17}{20}\)
\(x=\dfrac{363}{20}\)
a) \(\dfrac{3}{5}+x=\dfrac{1}{2}+1\)
\(\dfrac{3}{5}+x=\dfrac{3}{2}\)
\(x=\dfrac{3}{2}-\dfrac{3}{5}\)
\(x=\dfrac{15}{10}-\dfrac{6}{10}\)
\(x=\dfrac{9}{10}\)
b) \(3:x=\dfrac{2}{3}+2\dfrac{1}{2}\)
\(3:x=\dfrac{2}{3}+\dfrac{5}{2}\)
\(3:x=\dfrac{4}{6}+\dfrac{15}{6}\)
\(3:x=\dfrac{19}{6}\)
\(x=3:\dfrac{19}{6}\)
\(x=3\times\dfrac{6}{19}\)
\(x=\dfrac{18}{19}\)
Mik nhớ câu này làm rồi mak!!!
a,\(\dfrac{3}{5}\)+ x=\(\dfrac{1}{2}\)+1
\(\dfrac{3}{5}\)+x=\(\dfrac{3}{2}\)
x=\(\dfrac{3}{2}\)-\(\dfrac{3}{5}\)
x=\(\dfrac{9}{10}\)
b,
b) 3:x=23+2123:x=23+212
3:x=23+523:x=23+52
3:x=46+1563:x=46+156
3:x=1963:x=196
x=3:196x=3:196
x=3×619x=3×619
x=1819
\(\frac{3}{2}-x=-0,3:\frac{3}{5}\)
\(\frac{3}{2}-x=-\frac{1}{2}\)
\(x=\frac{3}{2}-\left(-\frac{1}{2}\right)\)
\(x=\frac{3}{2}+\frac{1}{2}=\frac{4}{2}=2\)
3/5.(3/2 - x) = -0.3
=>3/2 - x = -0.3 : 3/5
=>3/2 - x = -0.5
=> x = 3/2 + 0.5
=> x = 2
~Study well~