3/2 x 1/3 + 8/5 :4
giúp tui vs tui cần gấp!!!!!!!!!!
K
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MD
1
15 tháng 10 2023
\(\dfrac{2+\sqrt{2}}{\sqrt{2}+1}+\dfrac{1}{\sqrt{3}+\sqrt{2}}\)
\(=\dfrac{\sqrt{2}\left(\sqrt{2}+1\right)}{\sqrt{2}+1}+\dfrac{\sqrt{3}-\sqrt{2}}{3-2}\)
\(=\sqrt{2}+\sqrt{3}-\sqrt{2}=\sqrt{3}\)
TH
5
27 tháng 10 2020
B1. phân a tui ko bt nha :>
\(B=\frac{2^{13}\cdot9^4}{6^6\cdot8^3}\)
\(=\frac{2^{13}\cdot\left(3^2\right)^4}{\left(2\cdot3\right)^6\cdot\left(2^3\right)^3}\)
\(=\frac{2^{13}\cdot3^8}{2^6\cdot3^6\cdot2^9}\)
\(=\frac{2^{13}\cdot3^8}{2^{15}\cdot3^6}\)
\(=\frac{1\cdot3^2}{2^2\cdot1}\)
\(=\frac{1\cdot9}{4\cdot1}\)
\(=\frac{9}{4}\)
NP
2
4 tháng 1
a: \(\left\{{}\begin{matrix}3x-2y=4\\2x+y=5\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}3x-2y=4\\4x+2y=10\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}7x=14\\2x+y=5\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x=2\\y=5-2x=5-2\cdot2=1\end{matrix}\right.\)
b: \(\left\{{}\begin{matrix}-x+2y=2\\2x-y=-1\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}-2x+4y=4\\2x-y=-1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}3y=3\\x-2y=-2\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}y=1\\x=-2+2y=-2+2\cdot1=0\end{matrix}\right.\)
c: \(\left\{{}\begin{matrix}2x-y=13\\y-5=-7\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}2x-y=13\\y=-7+5=-2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=y+13=-2+13=11\\y=-2\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x=\dfrac{11}{2}\\y=-2\end{matrix}\right.\)
d: \(\left\{{}\begin{matrix}3x+y=8\\2x-3y=1\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}9x+3y=24\\2x-3y=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}11x=25\\3x+y=8\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x=\dfrac{25}{11}\\y=8-3x=8-3\cdot\dfrac{25}{11}=8-\dfrac{75}{11}=\dfrac{13}{11}\end{matrix}\right.\)
NH
3 tháng 3 2023
a)
`2/3+5/2-3/4`
`=10/4-3/4+2/3`
`=7/4+2/3`
`=21/12+8/12`
`=29/12`
b)
`2/5xx1/2:1/3`
`=2/10xx3/1`
`=6/10=3/5`
c)
`2/9:2/9xx1/3`
`=2/9xx9/2xx1/3`
`=1xx1/3`
`=1/3`
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
3 tháng 3 2023
a, \(\dfrac{2}{3}\) + \(\dfrac{5}{2}\) - \(\dfrac{3}{4}\)
= \(\dfrac{8}{12}\) + \(\dfrac{30}{12}\) - \(\dfrac{9}{12}\)
= \(\dfrac{38-9}{12}\)
= \(\dfrac{29}{12}\)
b, \(\dfrac{2}{5}\) x \(\dfrac{1}{2}\) : \(\dfrac{1}{3}\)
= \(\dfrac{1}{5}\) x \(\dfrac{3}{1}\)
= \(\dfrac{3}{5}\)
c, \(\dfrac{2}{9}\) : \(\dfrac{2}{9}\) x \(\dfrac{1}{3}\)
= 1 x \(\dfrac{1}{3}\)
= \(\dfrac{1}{3}\)
\(\frac{3}{2}\cdot\frac{1}{3}+\frac{8}{5}:4\\ =\frac{1}{2}+\frac{8}{5\cdot4}\\ =\frac{1}{2}+\frac{2}{5}\\ =\frac{5}{10}+\frac{4}{10}\\ =\frac{9}{10}\)
3/2.1/3+8/5:4
=1/2+8/5.1/4
=1/2+2/5
=5/10+4/10
=9/10
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