Tìm x biết
-7/2 : (3-x) - 0,75 = 1/4
| 2x - 4/3 | - 1 1/3 = -8/9
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\(A.\left(2a+1\right)^2-4\left(a+2\right)^2=9\\ \left(2a+1-2a-4\right)\left(2a+1+2a+4\right)=9\)
\(-3\left(4a+5\right)=9\\ -12a-15=9\\ -12a=24\\ a=-2\)
a,x- 2/3= -1/2
x= -1/2 + 2/3
x= 1/6
b,20%.x - x +1/5 =3/4
1/5.x - x +1/5 = 3/4
1/5.x-x =3/4 - 1/5
x.(1/5 - 1)=11/20
x.-4/5 =11/20
x=11/20 : -4/5=-11/16
a) \(x-\frac{2}{3}=-\frac{1}{2}\)
\(\Leftrightarrow x=\frac{2}{3}-\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{6}\)
b) \(20\%x-x+\frac{1}{5}=\frac{3}{4}\)
\(\Leftrightarrow\frac{1}{5}x-x=\frac{3}{4}-\frac{1}{5}\)
\(\Leftrightarrow-\frac{4}{5}x=\frac{11}{5}\)
\(\Leftrightarrow x=\frac{11}{5}:\left(-\frac{4}{5}\right)\)
\(\Leftrightarrow x=-\frac{11}{4}\)
a) 17 - 14( x + 1 ) = 13 - 4( x + 1 ) - 5( x - 3 )
<=> 17 - 14x - 14 = 13 - 4x - 4 - 5x + 15
<=> 17 - 14 - 13 + 4 - 15 = -4x - 5x + 14x
<=> -21 = 5x
<=> x = -21/5
b) 7( 4x + 3 ) - 4( x - 1 ) = 15( x + 0, 75 ) + 7
<=> 28x + 21 - 4x + 4 = 15x + 45/4 + 7
<=> 28x - 4x - 15x = 45/4 + 7 - 21 - 4
<=> 9x = -27/4
<=> x = -3/4
c) 3x( x + 1 ) - 2x( x + 2 ) = x2 - 1
<=> 3x2 + 3x - 2x2 - 4x = x2 - 1
<=> 3x2 + 3x - 2x2 - 4x - x2 = -1
<=> -x = -1
<=> x = 1
a, \(17-14\left(x+1\right)=13-4\left(x+1\right)-5\left(x-3\right)\)
\(\Leftrightarrow17-14x-14=13-4x-4-5x+15\)
\(\Leftrightarrow3-14x=24-9x\Leftrightarrow3-14x-24+9x=0\)
\(\Leftrightarrow-21-5x=0\Leftrightarrow5x=-21\Leftrightarrow x=-\frac{21}{5}\)
b, \(7\left(4x+3\right)-4\left(x-1\right)=15\left(x+0,75\right)+7\)
\(\Leftrightarrow28x+21-4x+1=15x+\frac{45}{4}+7\)
\(\Leftrightarrow9x=-\frac{27}{4}\Leftrightarrow x=-\frac{3}{4}\)
c, \(3x\left(x+1\right)-2x\left(x+2\right)=x^2-1\)
\(\Leftrightarrow3x^2+3x-2x^2-4x=x^2-1\)
\(\Leftrightarrow x^2-x=x^2-1\Leftrightarrow x=1\)
\(3\left(x-1\right)+4=28\)
\(\Rightarrow3x-3=28-4\)
\(\Rightarrow3x-3=24\)
\(\Rightarrow3x=24+3\)
\(\Rightarrow3x=27\)
\(\Rightarrow x=27\div3\)
\(\Rightarrow x=9\)
a.8x+28-9x+6=24
<=> -x+34=24
<=> -x=24-34
<=> x=10
b. 3-6x-x-18=7
<=> -7x=7+18-3
<=> -7x=22
<=> x=22/-7
A, 89-(73-x)=20
73-x =89-20
73-x =69
x = 73-69
x = 4
B, 62-(2x-3):3 = 23
(2x-3):3 = 62-23
(2x-3):3 = 39
2x-3 = 39.3
2x-3 = 117
2x = 117+3
2x = 120
x = 120:2
x = 60
C, 4(x-3) = 72 - 110
4(x-3) = 49 - 1
4(x-3) = 48
x-3 = 48:4
x-3 = 12
x = 12+3
x = 15
D, 32 (x+4)-52= 5.22
9(x+4)-25 = 5.4
9(x+4)-25 = 20
9(x+4) = 20+25
9(x+4) = 45
x+4 = 45:9
x+4 = 5
x = 5-4
x = 1
(Làm có hơi dài dòng nhưng đầy đủ lắm)
a, 89-(73-x)=20 b. 62-( 2x -3): 3=23 c, 4(x-3) = 72-11o d, 32 (x+4)-52 = 5.22
(73-x)=89-20 (2x - 3 ):3 = 62-23 4(x-3)=49-1 32(x+4) - 52= 5.4=20
73-x = 69 (2x - 3): 3= 39 4(x-3) =48 32(x+4)-25 =20
x = 73-69 (2x - 3)= 39: 3 x-3 = 48 :8 32(x+4)=20+25=45
x = 4 2x -3 =13 x-3 = 6 9(x+4)=45
2x= 13 + 3 x=6+3 x+4=45:9
2x= 16 x= 9 x+4=5
x=16:2 x=5-4
x= 8 x=1
chỗ nào ko hiểu cứ hỏi mik nhé
\(\left(x+2\right)-2=0\)
\(\Rightarrow x+2-2=0\)
\(\Rightarrow x=0\)
\(\left(x+3\right)+1=7\)
\(\Rightarrow x+3+1=7\)
\(\Rightarrow x+4=7\)
\(\Rightarrow x=3\)
\(\left(3x-4\right)+4=12\)
\(\Rightarrow3x-4+4=12\)
\(\Rightarrow3x=12\)
\(\Rightarrow x=4\)
\(\left(5x+4\right)-1=13\)
\(\Rightarrow5x+4-1=13\)
\(\Rightarrow5x+3=13\)
\(\Rightarrow5x=10\)
\(\Rightarrow x=2\)
\(\left(4x-8\right)-3=5\)
\(\Rightarrow4x-8-3=5\)
\(\Rightarrow4x-11=5\)
\(\Rightarrow4x=16\)
\(\Rightarrow x=4\)
\(8-\left(2x+4\right)=2\)
\(\Rightarrow8-2x-4=2\)
\(\Rightarrow4-2x=2\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=1\)
\(7+\left(5x+2\right)=14\)
\(\Rightarrow7+5x+2=14\)
\(\Rightarrow9+5x=14\)
\(\Rightarrow5x=5\)
\(\Rightarrow x=1\)
\(5-\left(3x-11\right)=1\)
\(\Rightarrow5-3x+11=1\)
\(\Rightarrow16-3x=1\)
\(\Rightarrow3x=15\)
\(\Rightarrow x=5\)
a) \(-\frac{7}{2}:\left(3-x\right)-0,75=\frac{1}{4}\)
\(\Leftrightarrow\frac{-7}{2\left(3-x\right)}=\frac{1}{4}+0,75=0,25+0,75=1\)
\(\Leftrightarrow2\left(3-x\right)=-7\)
\(\Leftrightarrow3-x=-\frac{7}{2}\)
\(\Leftrightarrow x=3+\frac{7}{2}\)
\(\Leftrightarrow x=\frac{13}{2}\)
b) \(\left|2x-\frac{4}{3}\right|-1\frac{1}{3}=-\frac{8}{9}\)
\(\Leftrightarrow\left|2x-\frac{4}{3}\right|=\frac{4}{3}-\frac{8}{9}=\frac{4}{9}\)
\(\Leftrightarrow\orbr{\begin{cases}2x-\frac{4}{3}=\frac{4}{9}\\2x-\frac{4}{3}=-\frac{4}{9}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=\frac{4}{3}+\frac{4}{9}=\frac{16}{9}\\2x=\frac{4}{3}-\frac{4}{9}=\frac{8}{9}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{8}{9}\\x=\frac{4}{9}\end{cases}}\)