Question

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so sánh

A=20¹⁰+1/ 20¹⁰-1 vả 20¹⁰-1/20¹⁰-3

Giúp mik vs mn ơi :) :)

Answer 1

[zZz Cool Kid_new zZz]

\(A=\frac{20^{10}+1}{20^{10}-1}=\frac{2^{10}-1+2}{20^{10}-1}=1+\frac{2}{20^{10}-1}\)

\(B=\frac{20^{10}-1}{20^{10}-3}=\frac{20^{10}-3+2}{20^{10}-3}=1+\frac{2}{20^{10}-3}\)

Dễ thấy \(20^{10}-1>20^{10}-3\)

\(\Rightarrow\frac{1}{20^{10}-1}< \frac{1}{20^{10}-3}\)

\(\Rightarrow1+\frac{1}{20^{10}-1}< 1+\frac{1}{20^{10}-3}\)

\(\Rightarrow A< B\)

Answer 2

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thanks bn nnnnnnnnhiu