Thực hiện phép tính
-3/4 . (-55/9) . 8/11
1 4/23 + ( 5/21 - 4/23) + 16/21 - 1/2
-3/8 . 6/13 + 7/13 . -3/8 + 1 3/8
75% - ( 5/2 + 5/3 ) + ( - 1/2) mũ 2
Giúp mình với đi please
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`a)1 4/23 + ( 5/21-4/23)+16/21-1/2`
`=27/23+5/21-4/23+16/21-1/2`
`=(27/23-4/23)+(5/21+16/21)-1/2`
`=23/23+21/21-1/2`
`=1+1-1/2`
`=2-1/2`
`=4/2-1/2`
`=3/2`
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`b)75%-(5/2+5/3)+(-1/2)^3`
`=3/4-5/2+5/3+(-1/8)`
`=(3/4-5/2-1/8)+5/3`
`=(6/8-20/8-1/8)+5/3`
`=-15/8+5/3`
`=-45/24+40/24`
`=-5/24`
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`c)-3/4(-55/9).8/11`
`=-3/4.(-40/9)`
`=-10/3`
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`d)-3/8 . 6/13 + 7/13 . (-3/8) + 1 3/8`
`= -3/8 . (6/13 + 7/13) + 11/8`
`= -3/8 . 13/13 + 11/8`
`= -3/8 .1 + 11/8`
`= -3/8 + 11/8`
`= 8/8`
`=1`
1: \(\dfrac{4}{23}+\dfrac{5}{21}+\dfrac{1}{2}-\dfrac{4}{23}+\dfrac{16}{21}\)
\(=1+\dfrac{1}{2}\)
\(=\dfrac{3}{2}\)
2: \(\left(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}\right)-\left(\dfrac{79}{67}-\dfrac{28}{41}\right)\)
\(=\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}-\dfrac{79}{67}+\dfrac{28}{41}\)
\(=\dfrac{1}{3}\)
`a)3/5+(-4/9)`
`=3/5-4/9`
`=27/45-20/45`
`=7/45`
`b)3/5+2/5 . 15/8`
`=3/5 + 30/40`
`=3/5+3/4`
`=12/20+15/20`
`=27/20`
`c)7/2 . 8/13 + 8/13 . (-5/2)`
`=8/13 . (7/2 +(-5)/2)`
`=8/13 . 1`
`=8/13`
`d)-5/17 . (-9/23)+9/23 . (-22/17) + 11 9/23`
`=-5/17 . (-9/23) + 9/23 . (-1) . 22/17 + 11 + 9/23`
`=-5/17 . (-9/23) + (-9/23) . 22/17+11+9/23`
`= -9/23 ( -5/17 + 22/17)+11+9/23`
`= - 9/23 . 1+11+9/23`
`=-9/23+11+9/23`
`=(-9/23+9/23)+11`
`=0+11`
`=11`
a: =27/45-20/45=7/45
b: =3/5+30/40
=3/5+3/4
=12/20+15/20
=27/20
c: =8/13(7/2-5/2+1)=8/13*2=16/13
d: =9/23*5/17-9/23*22/17+11+9/23
=-9/23+11+9/23
=11
- \(\dfrac{3}{4}\).(-\(\dfrac{55}{9}\)).\(\dfrac{8}{11}\)
= \(\dfrac{3.5.11.4.2}{4.3.3.11}\)
= \(\dfrac{10}{3}\)
1\(\dfrac{4}{23}\) + (\(\dfrac{5}{21}\) - \(\dfrac{4}{23}\)) + \(\dfrac{16}{21}\) - \(\dfrac{1}{2}\)
= 1 + \(\dfrac{4}{23}\) + \(\dfrac{5}{21}\) - \(\dfrac{4}{23}\) + \(\dfrac{16}{21}\) - \(\dfrac{1}{2}\)
= 1 + (\(\dfrac{4}{23}\) - \(\dfrac{4}{23}\)) + (\(\dfrac{5}{21}\) + \(\dfrac{16}{21}\)) - \(\dfrac{1}{2}\)
= 1 + 0 + 1 - \(\dfrac{1}{2}\)
= 2 - \(\dfrac{1}{2}\)
= \(\dfrac{3}{2}\)