-3/2 - x = -2/3 + 0,75
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1) 2,75 - 5/6 × 2/5 = 2,75 - (5/6) × (2/5) = 2,75 - 1/3 = 2,75 - 0,33 = 2,42
2) 1,25 - (5/6 - 0,75) - 3/5 = 1,25 - (5/6 - 0,75) - 3/5 = 1,25 - (5/6 - 3/4) - 3/5 = 1,25 - (5/6 - 9/12) - 3/5 = 1,25 - (10/12 - 9/12) - 3/5 = 1,25 - 1/12 - 3/5 = 1,25 - 0,08 - 0,6 = 1,25 - 0,68 = 0,57
3) 4/9 × 0,75 + 8/5 + 3,125 = (4/9) × 0,75 + 8/5 + 3,125 = 0,44 + 8/5 + 3,125 = 0,44 + 1,6 + 3,125 = 0,44 + 4,725 = 5,165
4) 1,125 - 4/7 - 0,12 = 1,125 - (4/7) - 0,12 = 1,125 - 0,57 - 0,12 = 0,435 - 0,12 = 0,315
5) (1/3 + 0,4) × 3,5 + (1/6 + 0,75) × 6/5
\(=0.75-\dfrac{7}{3}-0.75+9\cdot\left(-\dfrac{1}{9}\right)=-\dfrac{7}{3}-1=-\dfrac{10}{3}\)
= 0,75 x 0,25 + 0,75 x 1,25 - 0,75 x 0,5
= 0,75 x ( 0,25 + 1,25 - 0,5 )
= 0,75 x 1
= 0,75
=3/4.0,25+3/4.1,25-3/4.0,5
=3/4.(0,25+1,25-0,5)
=3/4.10
=15/2
1/2.x-2/3+0,75=1,25.2/3
1/2.x-2/3+3/4=5/4.2/3
1/2.x-2/3+3/4=5/6
1/2.x-2/3=5/6-3/4
1/2.x-2/3=1/12
1/2.x=1/12+2/3
1/2.x=3/4
x=3/4:1/2
x=6/4
x=1,5
a) \(0,75\times26+49\times\frac{3}{4}+\frac{3}{4}\times24+\) \(0,75\)
\(=\) \(0,75\times\left(26+1\right)+\frac{3}{4}\times\left(49+24\right)\)
\(=\) \(\frac{3}{4}\times27+\frac{3}{4}\times73\)
\(=\) \(\frac{3}{4}\times\left(27+73\right)\)
\(=\)\(\frac{3}{4}\times100=75\)
b) câu b,c làm tương tự
1, (0,25 - \(x\)) : - \(\dfrac{3}{5}\) = - \(\dfrac{3}{4}\)
0,25 - \(x\) = - \(\dfrac{3}{4}\) x (- \(\dfrac{3}{5}\))
0,25 - \(x\) = \(\dfrac{9}{20}\)
\(x\) = 0,25 - 0,45
\(x\) = - 0,2
2, - \(\dfrac{3}{8}\)\(x\) - 0,75 = - 1\(\dfrac{1}{2}\)
- \(\dfrac{3}{8}\)\(x\) - 0,75 = -1,5
\(\dfrac{3}{8}\)\(x\) = - 0,75 + 1,5
\(\dfrac{3}{8}\)\(x\) = 0,75
\(x\) = 0,75 : \(\dfrac{3}{8}\)
\(x\) = 2
a: \(\left(\dfrac{3}{4}x+2\dfrac{1}{2}\right)\cdot\dfrac{-2}{3}=\dfrac{1}{8}\)
=>\(\left(\dfrac{3}{4}x+\dfrac{5}{2}\right)=\dfrac{1}{8}:\dfrac{-2}{3}=\dfrac{-3}{16}\)
=>\(\dfrac{3}{4}x=-\dfrac{3}{16}-\dfrac{5}{2}=-\dfrac{3}{16}-\dfrac{40}{16}=-\dfrac{43}{16}\)
=>\(x=-\dfrac{43}{16}:\dfrac{3}{4}=\dfrac{-43}{16}\cdot\dfrac{4}{3}=\dfrac{-43}{12}\)
b: \(\dfrac{1}{3}\cdot x-0,5x=0,75\)
=>\(x\left(\dfrac{1}{3}-\dfrac{1}{2}\right)=0,75\)
=>\(x\cdot\dfrac{-1}{6}=0,75\)
=>\(x=-0,75\cdot6=-4,5\)
\(\frac{-3}{2}-x=\frac{-2}{3}+0,75\)
\(-x=\frac{3}{2}+\frac{-2}{3}+\frac{3}{4}\)
\(-x=\frac{19}{12}\)
\(x=\frac{-19}{12}\)
-3/2-x=-2/3+3/4
-3/2-x=1/12
x=-3/2-1/12
x=-19/12