Mọi ngừi giúp mình trước thứ năm nhé ( mơn )
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8km 832km = 840 km 753m = 0,753km
7km 37m = 7,037 km 42m = 0,042km
6km 4m = 6,004 km 3m = 0,003 km
chúc bạn học tốt nhé
1 The more dangerous things are, the more I like it
2 The older Mark is getting, the more and more like his grandfather he looks
3 The more I meet him, the more I know him
4 The longer she had to wait, the more impatient she got
5 The older a the chicken is, the tougher it is
6 The more careful a children is, the fewer mistakes he makes
7 The more expensive a diamon is, the more perfect it is
8 The more ripen the plum are, the sweeter they are
9 The more coffee you drink, the more nervous you will get
10 The more quickly people eat, the harder it is for them to digest
11 The closer to the center houses are, the more expensive thay are
13 The younger they are, the more quickly they learn
14 The bigger a supermarket is, the wider choice it has
15 The hotter the weather is, the more crowded the beaches are
16 The more I try to work this out, the more and more confused I am
Lời giải:
\(-3x^2+8x-2=0\)
\(\Leftrightarrow 3x^2-8x+2=0\)
\(\Leftrightarrow 3(x^2-\frac{8}{3}x+\frac{8^2}{6^2})=\frac{10}{3}\)
\(\Leftrightarrow 3(x-\frac{8}{6})^2=\frac{10}{3}\)
\(\Leftrightarrow (x-\frac{4}{3})^2=\frac{10}{9}\Rightarrow \left[\begin{matrix} x-\frac{4}{3}=\frac{\sqrt{10}}{3}\\ x-\frac{4}{3}=\frac{-\sqrt{10}}{3}\end{matrix}\right.\)
\(\Rightarrow \left[\begin{matrix} x=\frac{4+\sqrt{10}}{3}\\ x=\frac{4-\sqrt{10}}{3}\end{matrix}\right.\)
\(-3x^2+8x-2=0\)
\(\Leftrightarrow-3\left(x^2-\dfrac{8}{3}x+\dfrac{2}{3}\right)=0\)
\(\Leftrightarrow-3\left(x^2-2x.\dfrac{4}{3}+\dfrac{16}{9}-\dfrac{10}{9}\right)=0\)
\(\Leftrightarrow-3\left[\left(x-\dfrac{4}{3}\right)^2-\dfrac{10}{9}\right]=0\)
\(\Leftrightarrow\left(x-\dfrac{4}{3}\right)^2-\dfrac{10}{9}=0\)
\(\Leftrightarrow\left(x-\dfrac{4}{3}\right)^2=\dfrac{10}{9}\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{4}{3}=\dfrac{\sqrt{10}}{3}\\x-\dfrac{4}{3}=\dfrac{-\sqrt{10}}{3}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{\sqrt{10}+4}{3}\\x=\dfrac{4-\sqrt{10}}{3}\end{matrix}\right.\)
Vậy \(\left[{}\begin{matrix}x=\dfrac{\sqrt{10}+4}{3}\\x=\dfrac{4-\sqrt{10}}{3}\end{matrix}\right.\)
Ta có: \(2x=3y\Rightarrow\frac{x}{3}=\frac{y}{2}\Rightarrow\frac{x}{21}=\frac{y}{14}\left(1\right)\)
\(5y=7z\Rightarrow\frac{y}{7}=\frac{z}{5}\Rightarrow\frac{y}{14}=\frac{z}{10}\left(2\right)\)
Từ (1) và (2) \(\Rightarrow\frac{x}{21}=\frac{y}{14}=\frac{z}{10}\)
Áp dụng tính chất dãy tỉ số bằng nhau, ta có:
\(\frac{x}{21}=\frac{y}{14}=\frac{z}{10}=\frac{3x}{63}=\frac{7y}{98}=\frac{5z}{50}=\frac{3x-7y+5z}{63-98+50}=-\frac{30}{15}=-2\)
\(\frac{x}{21}=2\Rightarrow x=42\)
\(\frac{y}{14}=2\Rightarrow y=28\)
\(\frac{z}{10}=2\Rightarrow z=20\)
Vậy x = 42; y = 28; z = 20
tổng số tuổi 2 bố con hiện nay:
57+2+2=61(tuổi)
tuổi bố là:
(61+35):2=48(tuổi)
tuổi con là:
61-48=13(tuổi)
Đ/s:....
#HOCTOT
Câu 6B:
Gọi số đồng chí là x
Theo đề, ta có: \(x\in\left\{42;84;...\right\}\)
mà 39<x<46
nên x=42