thực hiện phép tính
a.80-[130-(-3+5^2]
b.-(-129)+(-119)-301+12
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a: \(-15-\left(-13+30\right)\)
\(=-15+13-30\)
\(=\left(-15-30\right)+13\)
=-45+13
=-32
b: \(225-150:\left(30+3^2\cdot5\right)\)
\(=225-150:\left(30+9\cdot5\right)\)
\(=225-150:75\)
=225-2
=223
c: \(18\cdot64+18\cdot36-1200\)
\(=18\left(64+36\right)-1200\)
\(=18\cdot100-12\cdot100\)
\(=6\cdot100=600\)
d: \(80-\left[130-\left(12-4\right)^2\right]\)
\(=80-130+\left(12-4\right)^2\)
\(=-50+8^2=64-50=14\)
80 – [130 – (12 - 4)2] = 80 – [130 – 82]
= 80 – [130 - 64] = 80 - 66 = 14
a) 5. 42 - 18 : 32 = 5 . 16 -18 : 9 = 80 - 2 = 78
b) 33 .18 -33 .12 = 33 . 6 = 27 .6 = 162
c) 39 . 213 + 87 . 39 = 39 . ( 213 + 87 ) = 39 . 300 = 11700
d) 80 - [ 130 - ( 12 - 4 ) .2 ] = 80 - (130 - 8.2 ) = 80 - 114 = -34
OK
\(80-\left[130-\left(12-4\right)^2\right]=80-\left[130-8^2\right]=80-\left[130-64\right]=80-66=14\)
a)
\(-12:\left(\dfrac{3}{4}-\dfrac{5}{6}\right)^2\)
\(=-12:\left(\dfrac{18}{24}-\dfrac{20}{24}\right)^2\)
\(=-12:\left(\dfrac{-1}{12}\right)^2\)
\(=-12:\dfrac{1}{144}\)
\(=-12\times\dfrac{144}{1}\)
\(=-1728\)
b)
\(\left(2^2:\dfrac{4}{3}-\dfrac{1}{2}\right)\times\dfrac{6}{5}-17\)
\(=\left(4\times\dfrac{3}{4}-\dfrac{1}{2}\right)\times\dfrac{6}{5}-17\)
\(=\left(3-\dfrac{1}{2}\right)\times\dfrac{6}{5}-17\)
\(=\dfrac{5}{2}\times\dfrac{6}{5}-17\)
\(=3-17\)
\(=-14\)
a)\(=-12:\left(-\dfrac{1}{12}\right)^2\)
\(=-12:\dfrac{1}{144}\)\(=-12.144=-1728\)
b)\(=\left(8:\dfrac{4}{3}-\dfrac{1}{2}\right).\dfrac{6}{5}-17\)
\(=\left(6-\dfrac{1}{2}\right).\dfrac{6}{5}-17\)
\(=\dfrac{11}{2}.\dfrac{6}{5}-17=\dfrac{33}{5}-17=\dfrac{33}{5}-\dfrac{85}{5}=-\dfrac{2}{5}\)
a) 36:32+23.22=9/8+506=(9+506.8)/8=(9+4048)/8=4057/8
b) 3.52-16:22=156-8/11=(156.11-8)/11=(1716-8)/11=1708/11
c) 80-[130-(12-4)2]=80-[130-8.2]=80-[130-16]=80-114=-34
a) \(80-[130-\left(-3+5^2\right)=\)\(80-[130-\left(-3+25\right)=\)\(80-\left(130-22\right)=\)\(80-108=-28\)
b)\(-\left(-129\right)+\left(-119\right)-301+12\)\(=129+\left(-119\right)-301+12=\)\(10-301+12=-279\)
chưa chắc là mk làm đúng đâu nhé!