tính
(1001/1007-2009/2015)x(1002/1008-2009/2015)x.....x(2014/2020-2009/2015)x(2015/2021-2009/2015)=
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\(\frac{x-1}{2015}+\frac{x-3}{2013}=\frac{x-5}{2011}+\frac{x-7}{2009}\)
=> \(\frac{x-1}{2015}-1+\frac{x-3}{2013}-1=\frac{x-5}{2011}-1+\frac{x-7}{2009}-1\)
=> \(\frac{x-2016}{2015}+\frac{x-2016}{2013}=\frac{x-2016}{2011}+\frac{x-2016}{2009}\)
=> \(\frac{x-2016}{2009}+\frac{x-2016}{2011}-\frac{x-2016}{2013}-\frac{x-2016}{2015}=0\)
=> \(\left(x-2016\right).\left(\frac{1}{2009}+\frac{1}{2011}-\frac{1}{2013}-\frac{1}{2015}\right)\)
Vì \(\frac{1}{2009}>\frac{1}{2013};\frac{1}{2011}>\frac{1}{2015}\)
=> \(\frac{1}{2009}+\frac{1}{2011}-\frac{1}{2013}-\frac{1}{2015}\ne0\)
=> \(x-2016=0\)
=> \(x=2016\)
Ta có :
\(x_1+x_2+x_3+...+x_{2015}=0\)
\(\left(x_1+x_2\right)+\left(x_3+x_4\right)+...+\left(x_{2013}+x_{2014}\right)+x_{2015}=0\)
\(\Rightarrow1+1+...+1+x_{2015}=0\)(có 1007 chữ số 1)
\(\Rightarrow1007+x_{2015}=0\)
\(\Rightarrow x_{2015}=0-1007\)
\(\Rightarrow x_{2015}=-1007\)
Vậy x2015 = -1007