27^4.9^3
các bạn tính giúp mik nhé ai làm đúng mik tik cho
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\(\left|2x+3\right|+2x=-4\)
\(\Leftrightarrow\left|2x+3\right|=-4-2x\)(1)
*Nếu \(x\ge\frac{-3}{2}\)thì \(2x+3\ge0\Rightarrow\left|2x+3\right|=2x+3\)
\(\Rightarrow\left(1\right)\Leftrightarrow2x+3=-4-2x\Leftrightarrow4x=-7\Leftrightarrow x=\frac{-7}{4}\left(L\right)\)
*Nếu \(x< \frac{-3}{2}\)thì \(2x+3< 0\Rightarrow\left|2x+3\right|=-2x-3\)
\(\Rightarrow\left(1\right)\Leftrightarrow-2x-3=-4-2x\Leftrightarrow0=-1\left(L\right)\)
Vậy pt vô nghiệm
\(\left|2x+3\right|+2x=-4\)
\(\Leftrightarrow\left|2x+3\right|=-4-2x\)
\(\Leftrightarrow\orbr{\begin{cases}2x+3=-4-2x\\2x+3=-\left(-4-2x\right)\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x+2x=-4-3\\2x+3=4+2x\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}4x=-7\\2x-2x=4-3\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-\frac{7}{4}\\0=1\left(loại\right)\end{cases}}\)
Vậy : \(x=-\frac{7}{4}\)
đặt A = |x + 1| + |x + 3|
ta có A = |x + 1| + |x + 3| = |x + 1| + |-x - 3| > |x + 1 -x - 3| = 2
=> Amin = 2 <=> (x+1)(-x-3) > 0
vậy Amin= 2 <=> -3< x <-1
a) \(3\left(2x-5\right)+125=134\)
\(\Leftrightarrow3\left(2x-5\right)=9\)
\(\Leftrightarrow2x-5=3\)
\(\Leftrightarrow2x=8\Leftrightarrow x=4\)
b) \(\left(2x+5\right)+\left(2x+3\right)+\left(2x+1\right)=27\)
\(\Leftrightarrow6x+9=27\)
\(\Leftrightarrow6x=18\Leftrightarrow x=3\)
d) \(27\left(x-27\right)-27=0\)
\(\Leftrightarrow27\left(x-27\right)=27\)
\(\Leftrightarrow x-27=1\Leftrightarrow x=28\)
Ta có:
\(x^3+x^2-4x=4\)
\(\Rightarrow x^3+x^2-4x-4=0\)
\(\Rightarrow\left(x^3+x^2\right)-\left(4x+4\right)=0\)
\(\Rightarrow x^2\left(x+1\right)-4\left(x+1\right)=0\)
\(\Rightarrow\left(x^2-4\right)\left(x+1\right)=0\)
\(\Rightarrow\left(x-2\right)\left(x+2\right)\left(x+1\right)=0\)
\(\Rightarrow x-2=0;x+2=0;x+1=0\)
\(\Rightarrow x\in\left\{2;-2;-1\right\}\)
a)\(2.\left(x+5\right)-x^2-5x=0\)
\(\Leftrightarrow2\left(x+5\right)-x\left(x+5\right)=0\)
\(\Leftrightarrow\left(x+5\right).\left(2-x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+5=0\\2-x=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-5\\x=2\end{cases}}\)
b)\(3x^3-48x=0\)
\(\Leftrightarrow3x\left(x^2-16\right)=0\)
\(\Leftrightarrow3x.\left(x-4\right).\left(x+4\right)=0\)
\(\Leftrightarrow\orbr{\frac{x=4}{\frac{x=0}{x=-4}}}\)
c)\(x^3+x^2-4x=4\)
\(\Leftrightarrow x^2\left(x+1\right)-4\left(x+1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x^2-4\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x-2\right)\left(x+2\right)\)
\(\Leftrightarrow\orbr{\begin{cases}\frac{x=0}{x=2}\\\overline{x=-2}\end{cases}}\)
\(27^4\cdot9^3=\left(3^3\right)^4.\left(3^2\right)^3=3^{12}\cdot3^6=3^{18}\)
\(=387420489\)
2.503315e+168
k mik nha bn