Question

[Akari]

1) Tìm x

a) \(\frac{11}{2}.\)\(x\)+\(\frac{1}{3}.\)x=1

2) so sánh

\(\frac{59}{40}\)và \(\frac{50}{31}\)

3) tính hợp lý

\(\frac{1}{3}+\frac{4}{7}-\frac{5}{14}-\frac{1}{2}-\frac{2}{3}\)

MONG MỌI NGƯỜI GIẢI GIÚP EM NHA. EM ĐANG CẦN GẤP. CẢM ƠN MỌI NGƯỜI NHIỀU

Answer 1

[Ahwi]

1) Tìm x

\(\frac{11}{2}.x+\frac{1}{3}.x=1\)

\(\Rightarrow x\left(\frac{11}{2}+\frac{1}{3}\right)=1\)

\(\Rightarrow x\left(\frac{33}{6}+\frac{2}{6}\right)=1\)

\(\Rightarrow x.\frac{35}{6}=1\)

\(\Rightarrow x=\frac{6}{35}\)

2) So sánh

\(\frac{59}{40}< \frac{50}{31}\)( cái này bạn quy đồng là ra, mik chỉ ghi kq, bạn tự tính )

3)\(\frac{1}{3}+\frac{4}{7}-\frac{5}{14}-\frac{1}{2}-\frac{2}{3}\)

\(=\left(\frac{1}{3}-\frac{2}{3}\right)+\left(\frac{4}{7}-\frac{5}{14}\right)-\frac{1}{2}\)

\(=-\frac{1}{3}+\frac{3}{14}-\frac{1}{2}\)

\(=-\frac{13}{21}\)

Answer 2

[Nguyễn Tấn Phát]

1)\(\frac{11}{2}.x+\frac{1}{3}.x=1\)

\(x.\left(\frac{11}{2}+\frac{1}{3}=1\right)\)

\(x.\frac{35}{6}=1\)

\(x=1:\frac{35}{6}\)

\(x=\frac{6}{35}\)

2) Ta có:

\(\frac{59}{40}=\frac{1829}{1240}\)

\(\frac{50}{31}=\frac{2000}{1240}\)

Vì \(2000>1829\Rightarrow\frac{2000}{1240}>\frac{1829}{1240}\Rightarrow\frac{50}{31}>\frac{59}{40}\)

3)\(\frac{1}{3}+\frac{4}{7}-\frac{5}{14}-\frac{1}{2}-\frac{2}{3}\)

\(=\left(\frac{1}{3}-\frac{2}{3}\right)+\left(\frac{4}{7}-\frac{5}{14}-\frac{1}{2}\right)\)

\(=-\frac{1}{3}+\left(\frac{8}{14}-\frac{5}{14}-\frac{7}{14}\right)\)

\(=\frac{-1}{3}+\frac{-4}{14}\)

\(=\frac{-1}{3}+\frac{-2}{7}\)

\(=\frac{-7}{21}+\frac{-6}{21}\)

\(=\frac{-13}{21}\)