Tính bằng cách thuậu tiện nhất
A)13/27+5/8+14/27=.......
B)4+11/25+39/25=.........
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`a: =(7/3-4/3)+11/5=16/5`
`b: =(18/13-5/13)+55/46=1+55/46=101/46`
`c: =27/25-4/9-2/25+5/9=(27/25-2/25)+(5/9-4/9)=1+1/9=10/9`
1. 36 x 25 x 4
= 36 x 100
= 3600
2. 18 x 24 : 9
= 18 : 9 x 24
= 2 x 24
= 48
3. 41 x 2 x 8 x 5
= 41 x 8 x 10
= 328 x 10
= 3280
4. 108 x (23+7)
= 108 x 30
= 3240
5. 215 x 86 + 215 x 14
= 215 x (86+14)
= 215 x 100
= 21500
6. 53 x 128 - 43 x 128
= (53-43) x 128
= 10 x 128
= 1280
\(\frac{21}{11}\times\frac{22}{17}\times\frac{68}{63}\)
=\(\frac{21}{1}\times\frac{2}{17}\times\frac{68}{63}\)
= 21 x \(\frac{8}{63}\)
=\(\frac{8}{3}\)
a: 14/25=98/175
5/7=125/175
mà 98<125
nên 14/25<5/7
b: 13/60=65/300
27/100=81/300
mà 65<81
nên 13/60<27/100
d: 47/15=329/105
65/21=325/105
mà 329>325
nên 47/15>65/21
e: 3/8=147/392
17/49=136/392
mà 147>136
nên 3/8>17/49
tính bằng cách thuận tiện nhất
a,4/15 x 7/8 + 4/15 x 2/9
b, 13/29 x 23/11 -13/19 x 8/11 - 13/19 x 4/11
Bài 1:
a; \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{7}{21}\) + (- \(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{1}{3}\) -\(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{10}{36}\)) + (\(\dfrac{8}{19}\) + \(\dfrac{11}{19}\)) - (\(\dfrac{1}{3}\) - \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{5}{18}\)) + \(\dfrac{19}{19}\) - 0 - \(\dfrac{5}{8}\)
= 0 + 1 - \(\dfrac{5}{8}\)
= \(\dfrac{3}{8}\)
b; \(\dfrac{1}{13}\) + (\(\dfrac{-5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\)) - (\(\dfrac{12}{17}\) - \(\dfrac{5}{18}\) + \(\dfrac{7}{5}\))
= \(\dfrac{1}{13}\) - \(\dfrac{5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{12}{17}\) + \(\dfrac{5}{18}\) - \(\dfrac{7}{5}\)
= (\(\dfrac{1}{13}\) - \(\dfrac{1}{13}\)) + (\(\dfrac{12}{17}\) - \(\dfrac{12}{17}\)) + (-\(\dfrac{5}{18}\) + \(\dfrac{5}{18}\)) - \(\dfrac{7}{5}\)
= 0 + 0 + 0 - \(\dfrac{7}{5}\)
= - \(\dfrac{7}{5}\)
Bài 1 c;
\(\dfrac{15}{14}\) - (\(\dfrac{17}{23}\) - \(\dfrac{80}{87}\) + \(\dfrac{5}{4}\)) + (\(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\))
= \(\dfrac{15}{14}\) - \(\dfrac{17}{23}\) + \(\dfrac{80}{87}\) - \(\dfrac{5}{4}\) + \(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\)
= (\(\dfrac{15}{14}-\dfrac{15}{14}\)) + (\(-\dfrac{17}{23}+\dfrac{17}{23}\)) - (\(\dfrac{5}{4}\) - \(\dfrac{1}{4}\)) + \(\dfrac{80}{87}\)
= 0 + 0 - 1 + \(\dfrac{80}{87}\)
= - \(\dfrac{7}{87}\)
a) 13/27 + 5/8 + 14/27 = (13/27 + 14/27) + 5/8 = 1 + 5/8 = 13/8
b) 4 + 11/25 + 39/25 = 4 + (11/25 + 39/25) = 4 + 50/25 = 4 + 2 = 6
a)\(\frac{13}{27}+\frac{5}{8}+\frac{14}{27}=\left(\frac{13}{27}+\frac{14}{27}\right)+\frac{5}{8}=1+\frac{5}{8}=\frac{13}{8}\)
\(=\frac{13}{8}\)
b)\(4+\frac{11}{25}+\frac{39}{25}=4+\left(\frac{11}{25}+\frac{29}{25}\right)=4+\frac{8}{5}\)
\(=\frac{28}{5}\)