Tìm x biết: (2/143+2/195+.................+2/399).x+221/231=4/3
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(2/11.13+2/13.15+...+2/19.21)-x+4+221/231=7/3
(1/11-1/13+1/13-1/15+...+1/19-1/21)-x+4+221/231=7/3
(1/11-1/21)-x+4+221/231 =7/3
(21/231-11/231)-x+4+221/231 =7/3
10/231-x+4+221/231 =7/3
(10/231+221/231)-x+4 =7/3
231/231-x+4 =7/3
1-x+4 =7/3
-x+5 =7/3
-x =7/3-5
-x =7/3-15/3
-x =-8/3
x =8/3
ĐẶt A = 2/11.13 + 2/13.15 +...+2/19.21
A = 1/11 - 1/13 +1/ 13 -1/15 +....+1/19 - 1/21
A = 1/11 - 1/21
A = 10/231
Thay vào ta có
10/231 - x + 4 + 221 /231 = 7/3
-x + 4 + 1 = 7/3 ( vì 10/231 + 221/231 = 1)
-x + 5 = 7/3
-x = 7/3 - 5
-x = -8/3
x = 8/3
\(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}-x+\frac{221}{231}=\frac{4}{3}\)
\(=2\left(\frac{1}{11.13}+\frac{1}{13.15}+...+\frac{1}{19.21}\right)-x+\frac{221}{231}=\frac{4}{3}\)
\(=2.\frac{1}{2}\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)-x+\frac{221}{231}=\frac{4}{3}\)
\(=\left(\frac{1}{11}-\frac{1}{21}\right)-x+\frac{221}{231}=\frac{4}{3}\)
\(=\frac{10}{231}-x+\frac{221}{231}=\frac{4}{3}\)
\(\frac{10}{231}-x=\frac{4}{3}-\frac{221}{231}\)
\(\frac{10}{231}-x=\frac{29}{77}\)
\(x=\frac{10}{231}-\frac{29}{77}\)
\(x=\frac{-1}{3}\)
a)\(\frac{5}{7}:X=1-\frac{4}{7}=\frac{3}{7}\)
\(X=\frac{5}{7}:\frac{3}{7}=\frac{5}{3}\)
b)
\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{14}+...+\frac{1}{19}-\frac{1}{21}\right)-X=\frac{4}{3}-\frac{221}{231}=\frac{29}{77}\)
\(\left(\frac{1}{11}-\frac{1}{21}\right)-X=\frac{29}{77}\)
\(X=\frac{10}{231}-\frac{29}{77}=-\frac{1}{3}\)
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BÀI 2
60%.x + 0,4.x + x:3= 2
\(\frac{60}{100}\)x + \(\frac{4}{10}\).x + x. \(\frac{1}{3}\)=2
\(\frac{3}{5}\).x + \(\frac{2}{5}\).x + x.\(\frac{1}{3}\)=2
(\(\frac{3}{5}\)+ \(\frac{2}{5}\)+ \(\frac{1}{3}\)) .x =2
\(\frac{4}{3}\).x =2
x = 2: \(\frac{4}{3}\)
x = \(\frac{3}{2}\)
Vậy x=\(\frac{3}{2}\)
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Bài 2 :
60%x + 0.4x + x : 3 = 2
\(x.\left(\frac{60}{100}+\frac{2}{5}+\frac{1}{3}\right)\)= 2
\(x.\frac{4}{3}\)= 2
\(x=2.\frac{3}{4}\)
\(x=1.5\)