1/72+1/56+1/42+1/30+1/20+1/12
lam ho em minh ca dang can gap
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TA CÓ:\(A=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}\)
\(=\frac{1}{2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\)
\(=\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)
\(=\frac{1}{2}+\frac{1}{2}-\frac{1}{8}\)
\(=1-\frac{1}{8}=\frac{7}{8}\)
em lớp 6 nha
B= 1/2 + 1/6 + 1/12 +1/20 + 1/30 + 1/42 + 1/56 + 1/72
B= 1/1*2 + 1/2*3 + 1/3*4 + 1/4*5 + 1/5*6 + 1/6*7 + 1/7*8 + 1/8*9
B=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9
B=1+0-0-0-0-0-0-0-1/9
B=1-1/9
B=8/9
k em nha
\(\left(x-2011\right)\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\cdot\frac{2}{9}=\frac{16}{9}\)
\(x-2011=8\)
\(x=2019\)
\(\frac{x-2011}{12}+\frac{x-2011}{20}+\frac{x-2011}{30}+\frac{x-2011}{42}+\frac{x-2011}{56}+\frac{x-2011}{72}=\frac{16}{9}\)
\(\left(x-2011\right)\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{8}-\frac{1}{9}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\left(\frac{1}{3}-\frac{1}{9}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\frac{2}{9}=\frac{16}{9}\)
\(x-2011=8\Rightarrow x=2019\)
1/20+1/30+1/42+1/56+1/72
=1/4x5+1/5x6+1/6x7+1/7x8+1/8x9
=1/4-1/5+1/5-1/6+...+1/9
=1/4-1/9
= 5 / 36
= 1/4x5 + 1/5x6 + 1/6x7 + 1/7x8 + 1/8x9
=1/4 - 1/5 + 1/5 - 1/6 +... + 1/8 - 1/9
= 1/4 - 1/9 = 5/36
\(\frac{20}{9}-x=\frac{1}{12}+\frac{1}{20}+.........+\frac{1}{72}\)
\(\Rightarrow\frac{20}{9}-x=\frac{1}{3.4}+\frac{1}{4.5}+.......+\frac{1}{8.9}\)
\(\Rightarrow\frac{20}{9}-x=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+........+\frac{1}{8}-\frac{1}{9}\)
\(\Rightarrow\frac{20}{9}-x=\frac{1}{3}-\frac{1}{9}\)
\(\Rightarrow\frac{20}{9}-x=\frac{2}{9}\)
\(\Rightarrow x=\frac{20}{9}-\frac{2}{9}\)
\(\Rightarrow x=\frac{18}{9}=2\)
20/9 -x= 1/3.4 +1/4.5+1/5.6+ 1/6.7+1/7.8+1/8.9
=1/3+1/4+1/4+1/5+1/5+1/6+1/6+1/7+1/7+1/8+1/8+1/9+1/9
20/9 -x= 1/3
x=20/9-1/3
x= 17/9
Nhớ tích (đúng) cho mình nha
\(\frac{20}{9}x=\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\)
\(\frac{20}{9}x=\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\)
\(\frac{20}{9}x=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-.....-\frac{1}{9}\)
\(\frac{20}{9}x=\frac{1}{3}-\frac{1}{9}=\frac{2}{9}\)
\(x=\frac{2}{9}:\frac{20}{9}=\frac{1}{10}\)
20/9 . x = 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72
20/9 . x = 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7 + 1/7.8 + 1/8.9
20/9 . x = 1/3 - 1/4 + 1/4 - 1/5 + ... + 1/8 - 1/9
20/9 . x = 1/3 - 1/9 = 2/9
x = 2/9 : 20/9 = 2/9 . 9/20 = 1/10
Vậy x = 1/10
=5/36
đúng thì k mình nhé
làm ơn giúp mình mình đang bị âm
A = 1/20 + 1/30 + 1/42 + 1/56 + 1/72
A= 1/4x5 + 1/5x6 + 1/6x7 + 1/7x8 + 1/8x9
A= 1/4 - 1/5 + ......................+ 1/8 - 1/9
A= 1/4 - 1/9
A= 5/36
\(\frac{1}{72}+\frac{1}{56}+\frac{1}{42}+\frac{1}{30}+\frac{1}{20}+\frac{1}{12}\)
\(=\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\)
\(=\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\)
\(=\frac{4-3}{3.4}+\frac{5-4}{4.5}+\frac{6-5}{5.6}+\frac{7-6}{6.7}+\frac{8-7}{7.8}+\frac{9-8}{8.9}\)
\(=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}\)
\(=\frac{1}{3}-\frac{1}{9}\)
\(=\frac{3}{9}-\frac{1}{9}\)
\(=\frac{2}{9}\)
1/72 = 1/9.1/8; 1/56 = 1/8.1/7; 1/42 = 1/7.1/6; 1/30 = 1/6.1/5; 1/20 = 1/5.1/4; 1/12 = 1/4.1/3
1/9 - 1/8 + 1/8 - 1/7 + 1/7 - 1/6 + 1/6 - 1/5 + 1/5 - 1/4 + 1/4 - 1/3 = 1/9 - 1/3 = -2/9
Tớ nghĩ là vậy, tớ đã tìm thấy 1 bài tương tự như vậy trên mạng rồi.