Question

[Nguyễn Tuệ Khanh]

Tìm a:
A= \(\dfrac{1}{1x4}\)+\(\dfrac{1}{1x7}\)+\(\dfrac{1}{7x10}\)+.....+\(\dfrac{1}{100x103}\)
 

Answer 1

[Linh Sam]

bài toán lớp mấy vậy?

Answer 2

[Lấp La Lấp Lánh]

\(A=\dfrac{1}{1\times4}+\dfrac{1}{4\times7}+\dfrac{1}{7\times10}+...+\dfrac{1}{100\times103}\)

\(=\dfrac{1}{3}\left(\dfrac{3}{1\times4}+\dfrac{3}{4\times7}+...+\dfrac{3}{100\times103}\right)\)

\(=\dfrac{1}{3}\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{100}-\dfrac{1}{103}\right)\)

\(=\dfrac{1}{3}\left(1-\dfrac{1}{103}\right)=\dfrac{1}{3}.\dfrac{102}{103}=\dfrac{34}{103}\)