2.53 -36:32
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a) \(-317+402-583+98\)
\(=85-583+98\)
\(=-498+98\)
\(=-400\)
\(24\cdot55+5^2\cdot53\)
\(=24\cdot55+25\cdot53\)
\(=1320+1325\)
\(=2645\)
24 x 55 + \(5^2\)x 53
= 1320 + 25 x 53
= 1320 + 1325
= 2645
\(62\cdot10:\left\{780:\left[103-\left(2\cdot53+35\cdot14\right)\right]\right\}\)
\(=62\cdot10:\left\{780:\left[103-596\right]\right\}\)
\(=620:\dfrac{-780}{493}\)
\(=620\cdot\dfrac{-493}{780}=\dfrac{-15283}{39}\)
\(a,\left\{\left[\left(37+13\right):5\right]-45:5\right\}.7\)
\(=\left\{\left[50:5\right]-45:5\right\}.7\)
\(=\left\{10-45:5\right\}.7\)
\(=\left\{10-9\right\}.7\)
\(=1.7=7\)
a) = 8 . 15 - [115- 72 ]
= 8 . 15 - [115- 49 ]
= 120 - 56
= 64
b) = 100 : {250 : [450 - (2.125 - 8.25)]}
= 100 : {250 : [450 - (250 - 200 )]}
= 100 : {250 : [450 - 50]}
= 100 : {250 :400}
= 100 : 0,265
= 0,00265
=
\(a,2^3.15-\left[115-\left(12-5\right)^2\right]\)
\(=8.15-\left[115-\left(12-5\right)^2\right]\)
\(=120-\left[115-7^2\right]\)
\(=120-\left[115-49\right]\)
\(=120-66\)
\(=54\)
\(b,100:\left\{250:\left[450-\left(2.5^3-2^3.25\right)\right]\right\}\)
\(=100:\left\{250:\left[450-\left(2.125-8.25\right)\right]\right\}\)
\(=100:\left\{250:\left[450-\left(250-200\right)\right]\right\}\)
\(=100:\left\{250:\left[450-50\right]\right\}\)
\(=100:\left\{250:400\right\}\)
\(=100:0,625\)
\(=160\)
-->C=\(\frac{1.2.3.4...99.100}{2.4.6....100}\)-->C=\(\frac{1.2.3...99.100}{\left(2.2....2\right)\left(1.2.3.4.5....50\right)}\)[50 chữ số 2]
-->\(C=\frac{51}{2}.\left(\frac{52}{2}\right)....\left(\frac{100}{2}\right)\)=D vậy C=D
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LI-KE CHO MK NHÉ BN
C=1.3.5.7...99
=>2.4.6...100.C=1.2.3...100
=>C = (1.2.3....100) / (2.4.6...100)= (1.2.3...50).(51.52...100) / [(2.1)(2.2).(2.3)...(2.50)]
C=(1.2.3...50).(51.52...100) /[2^50.(1.2.3...50)] =(51.52...100)/2^50 =51/2.52/2.53/2...100/2 =D
VAy C=D
=2.125 - 36: 9
=300 -4
= 296