1/3+1/3^2+1/3^4+................+1/3^100
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Exercise 5. Translate the following sentences into English.
1. I write faster and more carefully than my brother.
2. This year's summer vacation is just as sad as last year's summer vacation.
3. She is as pretty as her mother.
4. Huong's voice is much better than her own voice.
5. Hoa is much more studious than us.
1. I write faster and more carefully than my brother.
2. This year's summer vacation is just as sad as last year's summer vacation.
3. She's as pretty as her mother.
4. Huong's voice is so much more wonderful than her sister's voice.
5. Hoa is much more studious than us.
Đặt biểu thức cần tìm =A
Theo bài ra ta có:
A=2.1+3.(-1)+...+199(-1)+200.1
=2-3+4-5+...-199+200
=(-1)+(-1)+...+(-1)+200(có [(200-2):2=99 số -1]
=-99+200
=101
\(B=\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)\left(1-\frac{1}{5}\right)...\left(1-\frac{1}{2019}\right)\left(1-\frac{1}{2020}\right)\)
\(B=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}\cdot...\cdot\frac{2018}{2019}\cdot\frac{2019}{2020}\)
Số nào xuất hiện 2 lần thì thay thế những số đó bằng số 1.
\(B=\frac{1}{2020}\)
B = \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{2019}\right).\left(1-\frac{1}{2020}\right)\)
= \(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}...\frac{2018}{2019}.\frac{2019}{2020}\)
= \(\frac{1.2.3...2019}{2.3.4..2020}\)(Nếu có 2 thừa số giống nhau lặp lại ở tử số và mẫu số thì rút gọn coi như triệt tiêu hết và không có gì)
= \(\frac{1}{2020}\)
B=(1/5-1/5) + (-3/7+3/7) + (5/9-5/9) + (-2/11+2/11) + (7/13-7/13) - 9/16
= 0 + 0 + 0 + 0 + 0 - 9/16
=-9/16
\(B=\frac{1}{5}-\frac{3}{7}+\frac{5}{9}-\frac{2}{11}+\frac{7}{13}-\frac{9}{16}-\frac{7}{13}+\frac{2}{11}-\frac{5}{9}+\frac{3}{7}-\frac{1}{5}\)
\(B=\left(\frac{1}{5}-\frac{1}{5}\right)-\left(\frac{3}{7}-\frac{3}{7}\right)+\left(\frac{5}{9}-\frac{5}{9}\right)-\left(\frac{2}{11}-\frac{2}{11}\right)+\left(\frac{7}{13}-\frac{7}{13}\right)-\frac{9}{16}\)
\(B=0-0+0-0+0-\frac{9}{16}\)
\(B=0-\frac{9}{16}\)
\(B=-\frac{9}{16}\)
Bài này rất dễ sai dấu
Ủng hộ mk nha ^_-
\(\frac{1}{3}\)+\(\frac{1}{3^2}\)+...+\(\frac{1}{3^{100}}\)=(1-\(\frac{1}{3^{99}}\)):3=\(\frac{1}{3}\)