(2x-5).3-3=12
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a: \(A=\left|5x-3\right|-5\left(5-2x\right)\)
\(=\left|5x-3\right|-25+10x\)
TH1: x>=3/5
\(A=5x-3+10x-25=15x-28\)
TH2: x<3/5
\(A=3-5x+10x-25=5x-22\)
b: \(B=12-2x-\left|3-2x\right|\)
\(=-2x+12-\left|2x-3\right|\)
TH1: x>=3/2
\(B=-2x+12-\left(2x-3\right)\)
\(=-2x+12-2x+3=-4x+15\)
TH2: x<3/2
\(B=-2x+12-\left(3-2x\right)\)
\(=-2x+12-3+2x=9\)
a) \(\Rightarrow72-20x-36x+84=30x-240-6x-84\)
\(\Rightarrow80x=480\Rightarrow x=6\)
b) \(\Rightarrow15x+25-8x+12=5x+6x+36+1\)
\(\Rightarrow4x=0\Rightarrow x=0\)
c) \(\Rightarrow10x-16-12x+15=12x-16+11\)
\(\Rightarrow14x=4\Rightarrow x=\dfrac{2}{7}\)
1: Ta có: \(\dfrac{x+4}{4}+\dfrac{3x-7}{5}=\dfrac{7x+2}{20}\)
\(\Leftrightarrow5x+20+12x-28=7x+2\)
\(\Leftrightarrow17x-7x=2+8=10\)
hay x=1
2: Ta có: \(\dfrac{x}{6}+\dfrac{1-3x}{9}=\dfrac{-x+1}{12}\)
\(\Leftrightarrow\dfrac{6x}{36}+\dfrac{4\left(1-3x\right)}{36}=\dfrac{3\left(-x+1\right)}{36}\)
\(\Leftrightarrow6x+4-12x=-3x+3\)
\(\Leftrightarrow-6x+3x=3-4\)
hay \(x=\dfrac{1}{3}\)
3: Ta có: \(\dfrac{x-3}{3}-\dfrac{x+2}{12}=\dfrac{2x-1}{4}\)
\(\Leftrightarrow4x-12-x-2=6x-3\)
\(\Leftrightarrow3x-14-6x+3=0\)
\(\Leftrightarrow-3x=11\)
hay \(x=-\dfrac{11}{3}\)
4: Ta có: \(\dfrac{x-2}{4}-\dfrac{2x+3}{3}=\dfrac{x+6}{12}\)
\(\Leftrightarrow3x-6-8x-12=x+6\)
\(\Leftrightarrow-5x-x=6+18\)
hay x=-4
5: Ta có: \(\dfrac{2x-1}{12}-\dfrac{3-x}{18}=\dfrac{-1}{36}\)
\(\Leftrightarrow6x-3+2x-6=-1\)
\(\Leftrightarrow8x=8\)
hay x=1
\(\dfrac{2x-1}{12}=\dfrac{5}{3}\)
\(\Rightarrow\left(2x-1\right)3=12\cdot5\)
\(\Rightarrow6x-3=60\)
\(\Rightarrow6x=63\)
\(\Rightarrow x=\dfrac{21}{2}\)
\(\dfrac{2x-3}{15}=\dfrac{3}{5}\)
\(\Rightarrow\left(2x-3\right)5=15\cdot3\)
\(\Rightarrow10x-15=45\)
\(\Rightarrow10x=60\)
\(\Rightarrow x=6\)
#Đạt Đang Bận Thở
\(\dfrac{2x-1}{12}=\dfrac{20}{12}\)
\(\Leftrightarrow2x-1=20\)
\(\Leftrightarrow2x=21\)
\(\Leftrightarrow x=\dfrac{21}{2}\)
b. \(\dfrac{2x-3}{15}=\dfrac{9}{15}\)
\(\Leftrightarrow2x-3=9\)
\(\Leftrightarrow x=6\)
5.(3x+5)-4.(2x-3)=5x+3.(2x+12+1)
15x + 25 - 8x + 12 = 5x+6x + 36 + 3
7x + 37= 11x+ 39
11x-7x = 39-37
4x = 2
x= 1/2
\(5\left(3x+5\right)-4\left(2x-3\right)=5x+3\left(2x+12+1\right)\)
\(\Leftrightarrow15x+25-8x+12=5x+6x+39\)
\(\Leftrightarrow7x+37=11x+39\)
\(\Leftrightarrow-4x=2\)
\(\Rightarrow x=-\frac{1}{2}\)
\(5(3x+5)-4(2x-3)=5x+3(2x+12)+1\)
\(\Leftrightarrow15x+25-8x+12=5x+6x+36+1\)
\(\Leftrightarrow15x+25-8x+12-5x-6x-36-1=0\)
\(\Leftrightarrow-4x=0\)
\(\Leftrightarrow x=0\)
Ta có:
\(5\left(3x+5\right)-4\left(2x-3\right)=5x+3\left(2x+12\right)+1\\ 15x+25-8x+12=5x+6x+36+1\\ 7x+37=11x+37\\ 7x=11x\\ x=0\)
Vậy x = 0
\(d,=24x^2-38x+3\\ e,=x^2-12x+35\\ f,=\left(x^2-144\right)\left(4x-1\right)=4x^3-x^2-576x+144\)
Tìm x
a) (12x-5)(3x-1)-(18x-1)(2x+3)=5
b) (x+2)(x-3)-(x-2)(x+5)=2(x+3)
c) (2x+3)(2x-1)-(2x+5)-(2x-3)=12
\(\left(2x-5\right)\left(2x+5\right)-\left(2x-3\right)^2-12\)
\(=4x^2-25-4x^2+12x-9-12\)
\(=12x-46\)
a, \(4\left(18-5x\right)-12\left(3x-7\right)=15\left(2x-16\right)-6\left(x+14\right)\)
\(\Rightarrow72-20x-36x+84=30x-240-6x-84\)
\(\Rightarrow-20x-36x-30x+6x=-240-84-72-84\)
\(\Rightarrow-80x=-480\Rightarrow x=6\)
b, \(5\left(3x+5\right)-4\left(2x-3\right)=5x+3\left(2x+12\right)+1\)
\(\Rightarrow15x+25-8x+12=5x+6x+36+1\)
\(\Rightarrow15x-8x-5x-6x=36+1-25-12\)
\(\Rightarrow-4x=0\Rightarrow x=0\)
c, \(2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\)
\(\Rightarrow10x-16-12x+15=12x-16+11\)
\(\Rightarrow10x-12x-12x=-16+11+16-15\)
\(\Rightarrow-14x=-4\Rightarrow x=\dfrac{2}{7}\)
d, \(5x-3\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}=182\)
\(\Rightarrow5x-3\left[4x-2\left(4x-15x+6\right)\right]=182\)
\(\Rightarrow5x-3\left(4x-8x+30x-12\right)=182\)
\(\Rightarrow5x-12x+24x-90x+36=182\)
\(\Rightarrow-73x=182-36\)
\(\Rightarrow-73x=146\Rightarrow x=-2\)
Chúc bạn học tốt!!!
(2x-5).3-3=12
(2x-5).3=12+3
(2x-5).3=15
(2x-5)=15:3
(2x-5)=5
2x=5+5
2x=10
x=10:2
x=5
k cho mik ik