C=2+2^3+2^5+2^7+...+2^2009
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`#P.Vy`
`C=(3/3+2/3)(5/5+2/5)(7/7+2/7)...(2009/2009+2/2009)(2011/2011+2/2011)`
`C=5/3xx7/5xx9/7xx...xx2011/2009xx2013/2011`
\(C=\dfrac{5.7.9\times...\times2011.2013}{3.5.7\times...\times2009.2011}\)
`C=671`

C=5/3×7/5×9/7×...2011/2009×2013/2011
C=5×7×9×...×2011×2013/3×5×7×...×2009×2011
C=2013/3
C=674
Nếu sai bảo mình nhé !
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C=5/3.7/5.9/7....................2011/2009.2013/2011
=5.7.9...........2011.2013/3.5.7.............2009.2011
=2013/3
=671

a) -1 - 2 - 3 - 4 - 5 -.............- 2009 - 2010
SCSH: ( 2010 - 1 ) : 1 + 1 = 2010
tỔNG: ( 2010 + 1 ) . 2010 : 2 = 2021055
b) 1 - 3 + 5 - 7 +...............+ 2005 - 2007 + 2009 - 2011
SCSH: ( 2011 - 1 ) : 2 + 1 = 1006
tỔNG: ( 2011 + 1 ) . 1006 : 2 = 1012036
c) 1 - 2 - 3 + 4 + 5 - 6 - 7 +..........................+ 1997 - 1998 - 1999 + 2000 + 2001
SCSH: ( 2001 - 1 ) : 1 + 1 = 2001
tỔNG: ( 2001 + 1 ) . 2001 : 2 = 2003001
Hk tốt,
k nhé
\(C=2+2^3+2^5+2^7+...+2^{2009}\)
\(\Rightarrow2^2C=2^3+2^5+2^7+2^9+...+2^{2011}\)
\(\Rightarrow2^2C-C=2^3+2^5+2^7+2^9+...+2^{2011}-2+2^3+2^5+2^7+...+2^{2009}\)
\(\Rightarrow3C=2^{2011}-2\)
\(\Rightarrow C=\frac{2^{2011}-2}{3}\)