\(2^x\times2^{x+1}=10^{19}\div5^{19}\)
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19 x 1 = 19
19 x 2 = 38
19 x 3 = 57
19 x 4 = 76
19 x 5 = 95
19 x 6 = 114
19 x 7 = 133
19 x 8 = 152
19 x 9 = 172
19 x 10 = 190
Hok tốt ah
\(\dfrac{5\times4^{15}\times9^9-4\times3^{20}\times8^9}{5\times2^{10}\times6^{19}-7\times2^{29}\times27^6}\\ =\dfrac{5\times2^{30}\times3^{18}-2^2\times3^{20}\times2^{27}}{5\times2^{10}\times3^{19}\times2^{19}-7\times2^{29}\times3^{18}}\\ =\dfrac{5\times2^{30}\times3^{18}-2^{29}\times3^{20}}{5\times2^{29}\times3^{19}-7\times2^{29}\times3^{18}}\\ =\dfrac{2^{29}\times3^{18}\times\left(5\times2-3^2\right)}{2^{29}\times3^{18}\times\left(5\times3-7\right)}\\ =\dfrac{10-9}{15-7}\\ =\dfrac{1}{8}\)
= 2^19 x (3^3)^3 + 3 x 5 x (2^2)^9 x (3^2)^4 / 2^9 x 3^9 x 2^10 + (2^2)^10 x 3^10
= 2^19 x 3^9 + 3^9 x 2^18 x 5 / 2^19 x 3^9+2^20 x 3^10
= 3^9 x 2^18 x (2+5) / 3^9 x 2^19 x (1 + 2 x 3)
= 3^9 x 2^18 x 7 / 3^9 x 2^19 x 7 = 1/2
k mk nha
\(2^x\times2^{x+1}=10^{19}\div5^{19}\)
\(\Rightarrow2^{2x+1}=2^{19}\)
\(\Rightarrow2x+1=19\)
\(\Rightarrow2x=19-1\)
\(\Rightarrow2x=18\)
\(\Rightarrow x=18\div2\)
\(\Rightarrow x=9\)
\(2^x.2^{x+1}=10^{19}:5^{19}\)
\(2^{x+x+1}=\left(10:5\right)^{19}\)
\(2^{2x+1}=2^{19}\)
\(\Rightarrow2x+1=19\)
\(\Leftrightarrow2x=18\)
\(\Leftrightarrow x=9\)
Vậy \(x=9\)