1 : 10 x 100 + 90 =
K
Khách
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T
9
NN
1
NH
8 tháng 2 2023
b)
`15-3(3x+18)=36`
`=> 3(3x+18)=15-36`
`=> 3(3x+18)=-21`
`=> 3x+18=-21:3`
`=> 3x+18=-7`
`=> 3x=-7-18`
`=> 3x=-25`
`=> x=-25:3`
`=> x=-25/3`
c)
`-12+(3-x)=25`
`=>-12+3-x=25`
`=>-x=25+12-3`
`=>-x=34`
`=>x=-34`
d)
`100-90xx(x:2-1)=-10`
`=>90xx(x:2-1)=100-(-10)`
`=>90xx(x:2-1)=110`
`=>x:2-1=110:90`
`=>x:2-1=11/9`
`=>x:2=11/9 +1`
`=> x:2=20/9`
`=> x=20/9 xx2`
`=> x=40/9`
T
8
3 tháng 6 2019
1 + 90 x 3,14 = 283,6
90 + 10 x 100 = 1090
~ Ko có gì đâu :) ~
#JH
3 tháng 6 2019
1 + 90 x 3,14 = 283,6
90 + 10 x 100 = 1090
~ Ko có gì đâu :) ~
#JH
NQ
Tính bằng cách thuận tiện nhất :
a, 135 x 90 + 135 x 9 + 135
b, 95 x 8 + 95 + 95
c, 100 x 90 + 100 x 10
0
PO
17 tháng 1 2017
x + 90 = 100 + 10
x + 90 = 110
x = 110 - 90
x = 20 ai k mk,mk k lai
16 tháng 9 2016
Tính nhanh:
=250
Tìm x:
x=4
x=1000
x=2
k minh di minh k lai cho giup minh khoi phuc lai diem am nha!!!!!
H9
HT.Phong (9A5)
CTVHS
3 tháng 9 2023
a) \(\left(\dfrac{1}{2}+\dfrac{1}{6}+...+\dfrac{1}{90}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{9\cdot10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\left(1-\dfrac{1}{2}+\dfrac{1}{2}-...+\dfrac{1}{9}-\dfrac{1}{10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\left(1-\dfrac{1}{10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\dfrac{9}{10}\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow90-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)=90-89\)
\(\Rightarrow\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)=1\)
\(\Rightarrow x+\dfrac{103}{50}=\dfrac{5}{2}\)
\(\Rightarrow x=\dfrac{11}{25}\)
b) \(x\cdot9,85+x\cdot0,15=0,1\)
\(\Rightarrow x\cdot\left(9,85+0,15\right)=0,1\)
\(\Rightarrow x\cdot10=0,1\)
\(\Rightarrow x=\dfrac{0,1}{10}\)
\(\Rightarrow x=0,01\)
c) \(\dfrac{2}{5}+2022x=\dfrac{4}{10}\)
\(\Rightarrow\dfrac{2}{5}+2022x=\dfrac{2}{5}\)
\(\Rightarrow2022x=\dfrac{2}{5}-\dfrac{2}{5}\)
\(\Rightarrow2022x=0\)
\(\Rightarrow x=\dfrac{0}{2022}\)
\(\Rightarrow x=0\)
ND
Nguyễn Đức Trí
VIP
3 tháng 9 2023
a) \(\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{90}\right).100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\left(1\right)\)
Ta có :
\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{90}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{9}-\dfrac{1}{10}\)
\(=1-\dfrac{1}{10}=\dfrac{9}{10}\)
\(\left(1\right)\Rightarrow\dfrac{9}{10}.100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow90-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right].2=89\)
\(\Rightarrow\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right].2=90-89\)
\(\Rightarrow\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)=\dfrac{1}{2}\)
\(\Rightarrow x+\dfrac{206}{100}=\dfrac{5}{2}:\dfrac{1}{2}\)
\(\Rightarrow x+\dfrac{103}{50}=\dfrac{5}{2}.\dfrac{2}{1}\)
\(\Rightarrow x+\dfrac{103}{50}=5\)
\(\Rightarrow x=5-\dfrac{103}{50}\)
\(\Rightarrow x=\dfrac{250}{50}-\dfrac{103}{50}\)
\(\Rightarrow x=\dfrac{147}{50}\)
VT
0
Đáp án là 100 .
1:10x100+90=100