(x-2)^3=-8K/ x/-15= -60/x
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23 tháng 4 2016
1)240x15-80x6x3-60x4
=240x15-80x3x6-240x1
=240x15-240x6-240x1
=240x(15-6-1)
=240x8
=1920
2)150x5x3x6-15x11
150x5x6x3-15x10-150x0,2
=150x5x6x3-150x1-150x0,2
=150x(5+6+3-1-0,2)
=150x12,8
=1980
H9
HT.Phong (9A5)
CTVHS
24 tháng 9 2023
a) \(\dfrac{6}{13}:\left(\dfrac{1}{2}-x\right)=\dfrac{15}{39}\)
\(\dfrac{1}{2}-x=\dfrac{6}{13}:\dfrac{15}{39}\)
\(\dfrac{1}{2}-x=\dfrac{6}{5}\)
\(x=\dfrac{1}{2}-\dfrac{6}{5}\)
\(x=-\dfrac{7}{10}\)
b) \(3\times\left(\dfrac{x}{4}+\dfrac{x}{28}+\dfrac{x}{70}+\dfrac{x}{130}\right)=\dfrac{60}{13}\)
\(3\times x\times\left(\dfrac{1}{4}+\dfrac{1}{28}+\dfrac{1}{70}+\dfrac{1}{130}\right)=\dfrac{60}{13}\)
\(x\times\left(\dfrac{3}{1\times4}+\dfrac{3}{4\times7}+\dfrac{3}{7\times10}+\dfrac{3}{7\times13}\right)=\dfrac{60}{13}\)
\(x\times\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}\right)=\dfrac{60}{13}\)
\(x\times\left(1-\dfrac{1}{13}\right)=\dfrac{60}{13}\)
\(x\times\dfrac{12}{13}=\dfrac{60}{13}\)
\(x=\dfrac{60}{13}:\dfrac{12}{13}\)
\(x=5\)
11 tháng 2 2018
-2x - 40 = (5 - x) - (-15 + 60)
-2x - 40 = (5 - x) - 45
-2x - 40 = -40 - x
-2x - x = 40 - 40
-3x = 0
x = 0
2(x - 4) - 3(x + 7) = 14
2x - 8 - 3x - 21 = 14
-x - 29 = 14
-x = 14 + 29
-x = 43
x = -43
-7(5 - x) - 2(x - 10) = 15
-35 + 7x - 2x + 20 = 15
-15 + 5x = 15
5x = 15 + 15
5x = 30
x = 6
7 tháng 2 2021
a) Ta có: \(\dfrac{x}{-15}=\dfrac{-60}{x}\)
\(\Leftrightarrow x^2=\left(-15\right)\cdot\left(-60\right)=900\)
hay \(x\in\left\{30;-30\right\}\)
Vậy: \(x\in\left\{30;-30\right\}\)
b) Ta có: \(\left|x\right|+0.573=2\)
\(\Leftrightarrow\left|x\right|=1.427\)
hay \(x\in\left\{1.427;-1.427\right\}\)
Vậy: \(x\in\left\{1.427;-1.427\right\}\)
c) Ta có: \(\left|x+\dfrac{1}{3}\right|-4=-1\)
\(\Leftrightarrow\left|x+\dfrac{1}{3}\right|=3\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=3\\x+\dfrac{1}{3}=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{8}{3}\\x=-\dfrac{10}{3}\end{matrix}\right.\)
Vậy: \(x\in\left\{\dfrac{8}{3};-\dfrac{10}{3}\right\}\)
d) Ta có: \(0.01:2.5=\left(0.75x\right):0.75\)
\(\Leftrightarrow\dfrac{0.75\cdot x}{0.75}=\dfrac{0.01}{2.5}\)
\(\Leftrightarrow x=\dfrac{1}{250}\)
Vậy: \(x=\dfrac{1}{250}\)
14 tháng 9 2021
X – 60 : 15 = 20,5
=> X – 60 = 307,5
=> X = 367,5
X : 4 + 12 = 23
=> X : 4 = 11
=> X = 44
( x – 60 ) : 15 = 20
=> x – 60 = 300
=> x = 360
3 .(x + 7)- 15= 27
=> 3 .(x + 7) = 42
=> x + 7 = 14
=> x = 7
2. ( x – 5 )- 17 = 24 + 6 x 1,5
=> 2. ( x – 5 ) - 17 = 33
=> 2. ( x – 5 ) = 50
=> x - 5 = 25
=> x = 30
H
14 tháng 9 2021
\(a,x-60:15=20,5\)
\(x-4=20,5\)
\(x=20,5+4=24,5\)
\(b,x:4+12=23\)
\(x:4=23-12=11\)
\(x=11.4=44\)
\(c,\)\(\left(x-60\right)\)\(:15=20\)
\(x-60=20.15=300\)
\(x=300+60=360\)
\(d,3\left(x+7\right)\)\(-15=27\)
\(3\left(x+7\right)\)\(=27+15=42\)
\(x+7=42:3=14\)
\(x=14-7=7\)
\(e,2\left(x-5\right)\)\(-17=24+6.1,5=24+9=33\)
\(2\left(x-5\right)\)\(=33+17=50\)
\(x-5=50:2=25\)
\(x=25+5=30\)
=>........................
NT
0
a: (x-2)^3=-8
=>x-2=-2
=>x=0
b: =>x^2=900
=>x=30 hoặc x=-30