Em đang gấp , giúp vs ạ
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a/ Tam giác AMN cân tại A (gt). \(\Rightarrow\) \(\widehat{AMN}=\widehat{ANM};AM=AN.\)
Xét tam giác AMB và tam giác ANC có:
+ AM = AN (cmt).
+ \(\widehat{AMB}=\widehat{ANC}\left(\widehat{AMN}=\widehat{ANM}\right).\)
+ MB = NC (gt).
\(\Rightarrow\) Tam giác AMB = Tam giác ANC (c - g - c).
\(\Rightarrow\) AB = AC (cặp cạnh tương ứng).
Xét tam giác ABC có: AB = AC (cmt).
\(\Rightarrow\) Tam giác ABC cân tại A.
b/ Tam giác ABC cân tại A (cmt) \(\Rightarrow\) \(\widehat{ABC}=\widehat{ACB}.\)
Mà \(\widehat{ABC}=\widehat{MBH;}\widehat{ACB}=\widehat{NCK}\text{}\) (đối đỉnh).
\(\Rightarrow\) \(\widehat{MBH}=\widehat{NCK}.\)
Xét tam giác MBH và tam giác NCK \(\left(\widehat{BHM}=\widehat{CKN}=90^o\right)\)có:
+ MB = NC (gt).
+ \(\widehat{MBH}=\widehat{NCK}\left(cmt\right).\)
\(\Rightarrow\) Tam giác MBH = Tam giác NCK (cạnh huyền - góc nhọn).
c/ Tam giác MBH = Tam giác NCK (cmt).
\(\Rightarrow\) \(\widehat{BMH}=\widehat{CNK}\) (cặp góc tương ứng).
Xét tam giác OMN có: \(\widehat{NMO}=\widehat{MNO}\) (do \(\widehat{BMH}=\widehat{CNK}\)).
\(\Rightarrow\) Tam giác OMN tại O.
The doctor (already, examine)____________________ the patient.
Marconi (invent)________________ the telephone.
How many French tourists (meet)_______ she __________ last weekend?
They (repair)________________ their house all this month.
You (work)______________ too hard! That’s why you are tired.
When the doorbell (ring)_________, I (get)______ up and (answer)________it.
We (know)______________ her for years.
Her parents (live)__________ in Hue from 1985 to 1996.
The plant I bought (grow)______________ very much. And I water it every day.
We (meet)_________________ at 10 o’clock tonight.
Kate looks much thinner. She (lose)_____________ a lot of weight.
Look at those black clouds! It (rain)______________________.
Look! The fire engine (arrive)_________________.
Run! The bus driver (wait)_________________ for us!
Watch the baby! He (fall)__________________ off the bed.
Look at the sun! It (be)__________________ a very hot day!
It’s 7:30 in the morning and Mr. Brown (drive)_______________ to work, as usual.
Hurry up! We (miss)______________________ the train.
I (brush)_____________________ my teeth, have a wash and go to bed.
I (not have)_________________ breakfast this morning.
Câu 2:
#include <bits/stdc++.h>
using namespace std;
long long n,i,x,nn;
int main()
{
cin>>n>>x;
nn=x;
for (i=2; i<=n; i++)
{
cin>>x;
nn=min(nn,x);
}
cout<<nn;
return 0;
}
e) \(20\%\cdot1\dfrac{1}{4}\cdot12\cdot\dfrac{25}{45}\cdot0,6\)
\(=\dfrac{1}{5}\cdot\dfrac{5}{4}\cdot\dfrac{12}{1}\cdot\dfrac{5}{9}\cdot\dfrac{6}{10}\)
\(=1\)
Ta có: \(\left|x+\dfrac{1}{7}\right|\ge0\forall x,\left|y-12\right|\ge0\forall y\)
\(\Rightarrow A=\left|x+\dfrac{1}{7}\right|+\left|y-12\right|\ge0\)
\(minA=0\Leftrightarrow\) \(\left\{{}\begin{matrix}x+\dfrac{1}{7}=0\\y-12=0\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}x=-\dfrac{1}{7}\\y=12\end{matrix}\right.\)
\(A=\left|x+\dfrac{1}{7}\right|+\left|y-12\right|\)
Vì \(\left\{{}\begin{matrix}\left|x+\dfrac{1}{7}\right|\text{≥}0\\\left|y-12\right|\text{≥}0\end{matrix}\right.\)
⇒\(\left|x+\dfrac{1}{7}\right|+\left|y-12\right|\text{≥}0\)
Min \(A=0\)⇔\(\left\{{}\begin{matrix}x+\dfrac{1}{7}=0\\y-12=0\end{matrix}\right.\)
⇔\(\left\{{}\begin{matrix}x=-\dfrac{1}{7}\\y=12\end{matrix}\right.\)