A=35+45+34+n
N=33
N=4
N=F+56
F=30
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a ) 14 5 b ) − 31 20 c ) − 5 18
d ) 5 6 . e ) 1 2 . f ) 14 5
Lời giải chi tiết:
45 + 3 < 50 | 54 – 2 < 54 + 2 |
45 + 30 = 35 + 40 | 54 – 20 > 52 – 40 |
45 + 34 = 34 + 45 | 54 – 24 > 45 – 24 |
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3:
a: (a-b+c)-(c-b-a)
=a-b+c-c+b+a
=2a
b: \(-\left(a-b\right)+\left(b-c+a\right)-\left(a+b-c\right)\)
\(=-a+b+b-c+a-a-b+c\)
\(=b-a\)
c: \(-\left(a-b-c\right)-\left(-a+b+c\right)-\left(a-b+c\right)\)
\(=-a+b+c+a-b-c-a+b-c\)
\(=-a+b-c\)
2:
a: \(12-\left(-12\right)=12+12=24\)
b: \(-\left(35-49\right)+\left(27-49\right)=-35+49+27-49\)
=-35+27
=-8
c: \(47-\left(59-63\right)+\left(63-47\right)\)
\(=47-59+63+63-47\)
=126-59
=67
d: \(-\left(-20\right)-\left(-30\right)-70\)
=20+30-70
=50-70
=-20
FF = \(\frac{-4}{12}+\frac{18}{45}+\frac{-6}{9}+\frac{-21}{35}+\frac{6}{30}\)
F = \(\frac{-1}{3}+\frac{6}{15}+\frac{-2}{3}+\frac{-3}{5}+\frac{3}{15}\)
F = \((\frac{-1}{3}+\frac{-2}{3})+(\frac{6}{15}+\frac{3}{15})+\frac{-3}{5}\)
F = \(\frac{-3}{3}+\frac{9}{15}+\frac{-3}{5}\)
F = \(-1+\frac{3}{5}+\frac{-3}{5}\)
F =\(-1+0\)
F = \(-1\)
Vậy F = \(-1\)
35 * 34 + 35 * 34 + 65 * 75 + 65 * 45
= 34* ( 35+35) + 65* ( 75 + 45)
= 34 * 70 + 65* 120
= 2380 + 7800
= 10180
\(=35.\left(34+34\right)+65.\left(75+45\right)\)
\(=35.68+65.120=2380+7800=10180\)