X mũ 2 cộng 7x cộng 12
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1: Ta có: \(\left(7x-3^2\right):5=8\)
\(\Leftrightarrow7x-9=40\)
hay x=7
\(2^8\cdot3+2^8\cdot7+2^8\cdot6\)
\(=2^8\cdot\left(3+7+6\right)\)
\(=2^8\cdot16\)
\(=2^8\cdot2^4\)
\(=2^{12}\)
a)
\(\text{( 25 – 2x )³ : 5 – 3^2 = 4^2}\)
\(\text{( 25 – 2x )³ : 5 – 9 = 16}\)
\(\text{( 25 – 2x )³ : 5 = 16 + 9}\)
\(\text{( 25 – 2x )³ : 5 = 25}\)
\(\text{( 25 – 2x )³ = 25 . 5}\)
\(\text{( 25 – 2x )³ = 125}\)
\(\text{( 25 – 2x )³ = 5³}\)
\(\text{25 – 2x = 5}\)
\(\text{2x = 25 – 5}\)
\(\text{2x = 20}\)
\(\text{x = 10}\)
\(\text{________________________________________}\)
b)
\(\text{2.3^x = 10.3^12 + 8.27^4}\)
\(\text{2.3^x = 10.3^12 + 8.(3^3)^4}\)
\(\text{2.3^x = 3^12 . (10+8)}\)
\(\text{2.3^x = 3^12 . 18}\)
\(\text{3^x = 3^12 . 18:2}\)
\(\text{3^x = 3^12 . 9}\)
\(\text{3^x = 3^12 . 3^2}\)
\(\text{3^x = 3^14}\)
\(\text{=> x=14}\)
x2 + 7x + 12
= x2 + 3x + 4x + 12
= ( x2 + 3x ) + ( 4x + 12 )
= x( x + 3 ) + 4( x + 3 )
= ( x + 4 )( x + 3 )