Tìm x: x x 3 + x x 6 + x = 125 + 75 |
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a) \(75:\left(x-2\right)+4=7\)
\(\Rightarrow75:\left(x-2\right)=7-4\)
\(\Rightarrow75:\left(x-2\right)=3\)
\(\Rightarrow x-2=75:3\)
\(\Rightarrow x-2=25\)
\(\Rightarrow x=27\)
b) \(125-3\left(x+3\right)=65\)
\(\Rightarrow3\left(x+3\right)=125-65\)
\(\Rightarrow3\left(x+3\right)=60\)
\(\Rightarrow x+3=60:3\)
\(\Rightarrow x+3=20\)
\(\Rightarrow x=17\)
a,\(75:\left(x-2\right)+4=7\\ \Rightarrow75:\left(x+2\right)=3\\ \Rightarrow x+2=25\\ \Rightarrow x=23.\)
b, \(125-3\left(x+3\right)=65\\ \Rightarrow3\left(x+3\right)=60\\ \Rightarrow x+3=20\\ \Rightarrow x=17.\)
125 : x + 75 : x = 5
(125 + 75) : x = 5
200 : x = 5
x = 200 : 5
x = 40
125 : x + 75 : x = 5
(125 + 75) : x = 5
200 : x = 5
x = 200 : 5
x = 40
125 + 73950 : 75 + X x 196 = 2483
125 + 986 + X x 196 = 2483
1111 + X x 196 = 2483
X x 196 = 2483 - 1111
X x 196 = 1372
X = 1372 : 196
X = 7
MK chỉ làm câu b và c thôi nha
b)2x+|x-3|=6
TH1:2x+x-3=6
3x-3=6
3x=9
x=3
TH2:2x+-(x-3)=6
2x-x+3=6
x+3=6
x=3
Vậy x=3
c)3x-1=|2x-1|
TH1:3x-1=2x-1
3x-1-2x+1=0
x=0
TH2:3x-1=-(2x-1)
3x-1=1+2x
3x-1-1-2x=0
x-2=0
x=2
Vậy x=0;2
\(A=\left|x-125\right|+\left|x+75\right|\)
\(A=\left|125-x\right|+\left|75+x\right|\)
Ta có: \(\hept{\begin{cases}\left|125-x\right|\ge125-x\\\left|75+x\right|\ge75+x\end{cases}\Rightarrow\left|125-x\right|+\left|x+75\right|\ge125-x+x+75=200}\)
\(A=200\Leftrightarrow\hept{\begin{cases}\left|125-x\right|=125-x\\\left|75+x\right|=75+x\end{cases}\Leftrightarrow\hept{\begin{cases}125-x\ge0\\75+x\ge0\end{cases}\Leftrightarrow}\hept{\begin{cases}x\le125\\x\ge-75\end{cases}\Rightarrow}-75\le x\le125}\)
Vậy \(A_{min}=200\Leftrightarrow75\le x\le125\)
Tham khảo nhé~
\(x\times3+x\times6+x=125+75.\)
\(x\times3+x\times6+x\times1=200\)
\(x\times\left(3+6+1\right)=200\)
\(x\times10=200\)
\(x=200\div10\)
\(x=20\)
\(x\times3+x\times6+x=125+75\)
\(x\times3+x\times6+x\times1=125+75\)
\(x\times\left(3+6+1\right)=200\)
\(x\times10=200\)
\(x=200\div10\)
\(x=20\)